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Artemon [7]
3 years ago
11

title="( - 3) {}^{2} .( - 3) {}^{2} " alt="( - 3) {}^{2} .( - 3) {}^{2} " align="absmiddle" class="latex-formula">
plz tell me the answer ​
Mathematics
1 answer:
liq [111]3 years ago
4 0
The answer is 81. since (-3)^2 is 9. Therefore, 9x9=81.
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Use the information provided to write the standard form equation of each parabola. (Plzzzz help me)
Nikolay [14]

Answer:

I think you are in a test..You should do by your own

8 0
3 years ago
The equation 7(u-5)=21 is solved in several steps below. For each step, choose the reason that best justifies it.
krok68 [10]

Answer:

u = 8

Step-by-step explanation:

The steps are not shown. So, I will solve from scratch

Given

7(u -5) = 21

Required

Solve, with steps

7(u -5) = 21

Apply distributive  property

7u - 7 * 5 =21

7u - 35 =21

Collect like terms

7u = 35 + 21

7u = 56

Divide both sides by 7

\frac{7u}{7} = \frac{56}{7}

u = 8

4 0
3 years ago
Solve (x - 3)2 = 5.<br> O A. x = 8 and x = -2<br> B.<br> X = -35<br> C. X-5+13<br> Ô D. x = 3 + 6
Vinil7 [7]

Answer:

11/2

Step-by-step explanation:

7 0
3 years ago
In the following activity, write an equation to represent each verbal statement, and use it to find the value of each unknown nu
Julli [10]

The solution values in order from smallest to largest are;

  • -13 - First
  • -10 - Second
  • -3.5 - Third
  • -2 - Fourth
  • -0.75 - Fifth

<h3>Unknown equation</h3>

let

  • the unknown number = x

(x - 5)-2 = 14

-2x + 10 = 14

-2x = 14 - 10

-2x = 4

x = 4/-2

x = -2

4x - 5 = -8

4x = -8 + 5

4x = -3

x = -3/4

x = -0.75

(x + 3) / 5 = -2

x + 3 = -2(5)

x + 3 = -10

x = -10 - 3

x = -13

1/2x + 4 = -1

1/2x = -1 - 4

1/2x = -5

x = -5 ÷ 1/2

= -5×2/1

x = -10

x + 2 = 6/-4

-4(x + 2) = 6

-4x - 8 = 6

-4x = 6 + 8

-4x = 14

x = 14/-4

x = -3.5

Therefore, the smallest value is -13 and the largest value is -0.75.

Learn more about unknown equation:

brainly.com/question/12247728

#SPJ1

6 0
2 years ago
Explain how you are able to get the answer without having to multiply 1.23 by 10 thirteen times.​
max2010maxim [7]
We need more context to answer your question
5 0
3 years ago
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