Note that <span>x^2+y^2=16x−26y−133 represents a circle.
x^2 - 16x + y^2 + 26y = 133
x^2 - 16x + 64 - 64 + y^2 + 26y + 169 - 169 = 133 (completing the square)
Then (x-8)^2 - 64 + (y+13)^2 - 169 = 133
Simplifying, (x-8)^2 + (y+13)^2 = 133 + 169 + 64 = 366
This circle acts as a constraint on the value of 6x-8y. Assume that x and y are both on the circle. Just supposing that x = 10, find y:
(10-8)^2 + (y+13)^2 = 366, or 4 + (y+13)^2 = 366, or (y+13)^2 = 362
This is a quadratic equation that could be solved for y, and the result(s) could be subst. into the expression 6x-8y.
If you were to repeat this exercise several times, for different values of x, you'd come up with various values of 6x-8y and in that way approach (if not find) a definite answer to "</span><span>Given that x2+y2=16x−26y−133, what is the biggest value that 6x−8y can have?"
Hope someone else can come up with a more elegant approach.</span>
Answer:
none of these are true
Step-by-step explanation:
Commutative property basically states that u can " commute " ...move the numbers around
so the commutative property of 2 * 10 * 7 could be 7 * 2 * 10... or 10 * 7 * 2...or 10 * 2 * 7 or 2 * 7 * 10....I think u get what I mean
Answer:
C. 38.85 ft
Step-by-step explanation:
Draw a picture of the triangle formed by Wendy, the car, and the base of the building. The side of the triangle opposite of the 75° angle is 145 feet. The side of the triangle adjacent to the angle is x. Use tangent:
tan 75 = 145 / x
x = 145 / tan 75
x = 38.85
The car is 38.85 feet from the base of the building.
Y2-y1 / x2-x1
so, 3-1 =2 and 4-3=1
2/1 is 2
