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riadik2000 [5.3K]

3 years ago

10

Ms.Corley wants to take her class on a trip to either the nature center or zoo. The nature center charges $4 per student plus$95

for a 1-hour naturalist program. the zoo charges $9 per student plus $75 fro a 1-hour guided tour. a. Write a system of equations to represent this situation b. solve the system of equations algebraically and by graphing. Intercept the solution. c. Ms.Corley has 22 students in her class. Determine which would cost less, the nature center or zoo.

1 answer:

Kazeer [188]3 years ago

6 0

zoo is the answer....................................................................

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What is the relationship between the unfinished puzzle and the missing piece

Mrac [35]

I would say that the unfinished puzzle has more than one piece and the missing piece is only one, itself.

7 0

3 years ago

If x and y satisfy both 9x+2y=8 and 7x+2y=4, then y=?

Alex

Answer:

The value of y is -5

Step-by-step explanation:

we have

$9x+2y=8$ ------> equation A

$7x+2y=4$ ------> equation B

we know that

If x and y satisfy both equations, then (x,y) is the solution of the system of equations

Using a graphing tool

Remember that

The solution of the systems of equations is the intersection point both graphs

The intersection point is (2,-5)

therefore

The solution of the system of equations is the point (2,-5)

The value of y is -5

7 0

3 years ago

mihalych1998 [28]

Answer:

$=4.+2.$

Step-by-step explanation:

<u>Linear Combination Of Vectors </u>

One vector $\vec b$ is a linear combination of $\vec a_1$ and $\vec a_2$ if there are two scalars $x_1, x_2$ such as

$\vec b=x_1\vec a_1+x_2\vec a_2$

In our case, all the vectors are given in $R^3$ but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.

We have

$\vec a_1=,\ \vec a2=,\ \vec b=$

We set the equation

$=x_1.+x_2.$

Multiplying both scalars by the vectors

$=+$

Equating each coordinate, we get

$4x_1-4x_2=8$

$5x_1+3x_2=26$

$-4x_1+3x_2=-10$

Adding the first and the third equations:

$-x_2=-2$

$x_2=2$

Replacing in the first equation

$4x_1-4(2)=8$

$4x_1=8+8$

$x_1=4$

We must test if those values make the second equation become an identity

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The second equation complies with the values of $x_1$ and $x_2$ , so the solution is

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8 0

3 years ago

Can someone please explain The measure of angle A to the nearest tenth of a degree is:

Ratling [72]

Answer:

A =19.5

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin A= opp/ hyp

sin A = 3/9

Take the inverse sin of each side

sin ^-1 sin A = sin ^-1 (3/9)

A =19.47122063

To the nearest tenth of a degree

A =19.5

3 0

3 years ago

Read 2 more answers

Solve this system of linear equations. separate x and y values with a comma. 7x=-67-11y 5x=-73-11y

Aleks [24]

Answer:

3, -8

(x is equal to 3 and y is equal to -8)

Step-by-step explanation:

<u>The system:</u>

{ 7x=-67-11y

{ 5x=-73-11y

<u>Finding a value for x:</u>

7x=-67-11y -> x = $-\frac{67}{7}$ - $\frac{11y}{7}$

<u>Solving for y by plugging in our x:</u>

[Equation] 5x = -73 -11y

[Plug-in] 5( $-\frac{67}{7}$ - $\frac{11y}{7}$ ) = -73 -11y

[Distribute the 5] $-\frac{335}{7}$ - $\frac{55y}{7}$ = -73 -11y

[Multiply by 7] 7 ( $-\frac{335}{7}$ - $\frac{55y}{7}$ ) = (-73 -11y) 7

[Simplify] -335 - 55y = -511 - 77y

[Add 335 and 77y to both sides] 22y = -176

[Divide by 22] y = -8

<u>Plug in our y to solve for x:</u>

5x = -73 -11y

5x = -73 -11(-8)

5x = -73 + 88

5x = 15

x = 3

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

5 0

3 years ago