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Mariulka [41]
3 years ago
10

A public school in your city has 1710 girls among the 2970 students. What is the ratio of boys to girls in school

Mathematics
1 answer:
Minchanka [31]3 years ago
3 0

Answer:

The simplest answer would just be 14:19

However the unsimplified answer is 1260:1710

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Can someone help me with this one
bonufazy [111]

Answer:

x(2x+1)(x-2)

Step-by-step explanation:

x(2x^2-3x-2)

x(2x^2-4x+x-2)

x[2x(x-2)+1(x-2)]

x(2x+1)(x-2)

3 0
3 years ago
What is “8 - 4(-x + 5)” equivalent too?
RSB [31]

Answer:

4x -12

Step-by-step explanation:

8 - 4(-x + 5)

Distribute

8 -4(-x) -4(5)

8 +4x -20

4x -12

4 0
2 years ago
Read 2 more answers
What is the area of the triangle?
Dahasolnce [82]

Answer:

4

Step-by-step explanation:

The formula of the area of a triangle is 1/2 times base times height

1/2 .4.2 equals 4

7 0
3 years ago
Imara used these steps to find the length of the hypotenuse of the right triangle.
mojhsa [17]
Imara used these steps to find the length of the hypotenuse of the right triangle.

3 squares are positioned to form a right triangle. The small square is labeled 15, medium square is 20, and large square is not labeled.

Step 1: Find the area of the square with side lengths of 20: 400
Step 2: Find the area of the square with side lengths of 15: 225
Step 3: Find the sum of the areas of the two squares: 625
Step 4: State the length of the hypotenuse: 625

Which best describes Imara’s error?
She should have found the area of the square with side lengths of 15 first.
She did not correctly calculate the area of the square with side lengths of 15.
She should have found the sum of 15 and 20 and then squared the sum.
She did not find the side lengths of the square with an area of 625.
7 0
3 years ago
Read 2 more answers
No matter which natural number "n" that you choose, explain why the following statement can never be true:
maria [59]
First of all, 2^n and 3^n are exponentials with different bases, and thus their sum cannot be simplified beyond 2^n + 3^n.  In other words, these two functions cannot be combined ino one function (such as 4^n).

You may gain much more insight by graphing 2^n, 3^n and 4^n to determine whether there is truth in the given statement or not.

3 0
3 years ago
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