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DaniilM [7]
3 years ago
14

a bag contains 5 blue, 8 red, and 7 green marbles. a marble is selected at random. find the probability the marble is not red

Mathematics
2 answers:
Alchen [17]3 years ago
6 0
3/5 is the same as 12/20 which is not red over total
qaws [65]3 years ago
6 0
12/20 ( colors not red/ Total) 
= Simplified
= 6/10
=3/5

Hope this Helps!
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7. Use the quotient rule to simplify the following expression. Assume that x>0.
NeTakaya
Quotient rule says we can divide 192 and 3 because they are both under the radical. This gives us the square root of 64.

We can also divide x^3 and x to get x^2.

The square root of 64x^2 is 8x
8 0
3 years ago
Leah is writing an equivalent equation which solves for y. What should be her next step? 3x+4y=8 Add 4y to both sides of the equ
ratelena [41]

The given equation is

3x+4y=8

And we have to solve for y.

Solving for y, means isolating y . And to isolate y, we need to get rid of 4 that is with y .

It means we have to separate 4 from y, and for separation , we have to perform division. That is, we have to divide both sides by 4, and that will be the next step .

So out of the four options, correct option is the last option .

4 0
3 years ago
Read 2 more answers
Look at the two-dimensional net shown. A rectangular pyramid. The rectangular base has a length of 10 meters and height of 3 met
valentina_108 [34]

Answer: Here.

The Solid formed by the net will be a rectangular pyramid.

There are TWO sets of opposite congruent triangular faces.

The base has an area of 30m2

Step-by-step explanation: Don't listen to the B and C dude.

3 0
3 years ago
Read 2 more answers
The sum of three numbers is 8. The third is 9
Ierofanga [76]

Answer:

→<u> </u><u>First</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>1</u>

→<u> </u><u>Second</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>2</u>

→<u> </u><u>Third</u><u> </u><u>value</u><u> </u><u>is</u><u> </u><u>5</u>

Step-by-step explanation:

• let numbers be x, y and z

{ \tt{z = 8y - 9 -  -  - (eqn \: 1)}} \\  \\ { \tt{10x = 8y - 7 -  -  - (eqn \: 2)}} \\  \\ { \tt{x + y + z = 8 -  -  - (eqn \: 3)}}

• from eqn 2, make x the subject:

{ \tt{x =  \frac{8y - 7}{10} }} \\

• substitute all variables in eqn 3:

{ \tt{ \frac{8y - 7}{10}  + y + 8y - 9 = 8}} \\  \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\  \\ { \tt{98y = 177}} \\  \\ { \boxed{ \tt{ \: y = 1.8}}}

• find z

{ \tt{z = 8y - 9}} \\  \\ { \tt{z = 8(1.8) - 9}} \\  \\ { \tt{z = 14.4 - 9}} \\  \\ { \boxed{ \tt{ \: z = 5.4 \: }}}

• find x:

{ \tt{x =  \frac{8(1.8) - 7}{10} }} \\  \\ { \tt{x =  \frac{7.4}{10} }} \\  \\ { \boxed{ \tt{ \: x = 0.74 \: }}}

Rounding to nearest value:

{ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{  \rm{z = 5}}}

7 0
3 years ago
I need help, look at the picture.
worty [1.4K]
The order would be
A
C
B
7 0
4 years ago
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