2 years ago

Anyone wanna be egirl

Mathematics

1 answer:

GaryK [48]2 years ago

5 0

Answer:

It’s crossed my mined a couple times

Step-by-step explanation:

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Note: enter your answer and show all the steps that you use to solve this problem in the space below.

Serjik [45]

Answer:

thats tough

Step-by-step explanation:

thats tough u should get a tutor bruh

3 0

3 years ago

Help!?!?<br>a. 13.12<br>b.13.20<br>c.12.75<br>d.12.96

MA_775_DIABLO [31]

Solved it!!! I hope it helps. Please say thanks and give 5 stars.

5 0

2 years ago

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What's the product of 3 2⁄3 and 14 2⁄5 ?

polet [3.4K]

3 2/3=11/3
14 2/5=72/5

11/3x72/5=264/5
264/5=52 4/5

5 0

3 years ago

Which number line best shows how to solve -2-(-4)

pantera1 [17]

Alright. -2-(-4) = -2 + 4 because a negative and a negative equals to a positive[(-2-(-4)]. It would look like: Put a dot on -2, then move your dot 4 units to the right, which is +2.

6 0

3 years ago

Read 2 more answers

Verify the identity. Show your work. (1 + tan^2u)(1 - sin^2u) = 1

yuradex [85]

$\bf \textit{Pythagorean Identities}
\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\\
[1+tan^2(u)][1-sin^2(u)]=1
\\\\\\\
[sec^2(u)][cos^2(u)]\implies \cfrac{1}{cos^2(u)}\cdot cos^2(u)\implies \cfrac{cos^2(u)}{cos^2(u)}\implies 1$

7 0

3 years ago