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3 years ago

Anyone wanna be egirl

Mathematics

1 answer:

GaryK [48]3 years ago

5 0

Answer:

It’s crossed my mined a couple times

Step-by-step explanation:

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Wolf brothers help me out, please no link

soldi70 [24.7K]

Answer:

21 cards left to be signed

Step-by-step explanation:

1/3 of 72 is 24

So Harrison signed 24

3/8 of 72 is 27

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24+27=51

So 72-51=21

21 cards left to be signed

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2 years ago

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Paladinen [302]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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Find the generating function for the sequence 1,1,1,2,3,4,5,6,....

marin [14]

Answer:

$P(x)=\dfrac{1}{1-x}+\dfrac{x^3}{(1-x)^2} \quad \text{for} \mid x \mid < 1$ [/tex]

Step-by-step explanation:

The generating function of a sequence is the power series whose coefficients are the elements of the sequence. For the sequence

$1,1,1,2,3,4,5,6,...$

the generating function would be

$P(x)=1+x+x^2+2x^3+3x^4+4x^5+5x^6+...\\$

we can multiply P(x) by x to get

$xP(x)=x+x^2+x^3+2x^4+3x^5+4x^6+...$

Note that

$P(x)-xP(x)=1+(2x^3-x^3)+(3x^4-2x^4)+(4x^5-3x^5)+(5x^6-4x^6)+...\\ \\=1+x^3+x^4+x^5+x^6+...=1+x^3(1+x+x^2+x^3+x^4+...)$

which for $\mid x \mid < 1$ can be rewritten as

$(1-x)P(x)=1+\dfrac{x^3}{(1-x)} \quad \Rightarrow \\\\P(x)=\dfrac{1}{(1-x)}+\dfrac{x^3}{(1-x)^2}$

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3 years ago

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lesantik [10]

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3 years ago