Answer:
Here's what I've done:
Let ϵ>0ϵ>0 be given.
Now,
|f(x)−f(y)|=|tan−1x−tan−1y|=∣∣tan−1(x−y1+xy)∣∣
|f(x)−f(y)|=|tan−1x−tan−1y|=|tan−1(x−y1+xy)|
For non-negative x,y∈R,x,y∈R,
|f(x)−f(y)|=|tan−1x−tan−1y|=∣∣tan−1(x−y1+xy)∣∣≤|tan−1(x−y)|≤|x−y|<δ
|f(x)−f(y)|=|tan−1x−tan−1y|=|tan−1(x−y1+xy)|≤|tan−1(x−y)|≤|x−y|<δ
We can choose ϵ=δϵ=δ. Now, for negative x,y∈Rx,y∈R. Please, how do I go about it?
Answer:
3
Step-by-step explanation:
We know x = -2, so we can substitute -2 in for x
3x^2- 9
3*-2^2-9
Solve the exponent first (PEMDAS)
3*4-9
Multiply next
12-9
Subtract
3
Let from the height at which ball was thrown = h units
It is given that , ball rebounds the same percentage on each bounce.
Let it rebounds by k % after each bounce.
Height that ball attains after thrown from height h(on 1 st bounce)=
Height that ball attains after thrown from height h (on 2 n d bounce)=
Similarly, the pattern will form geometric sequence.
S=
So, Common Ratio =
Common Ratio= 1 + the percentage by which ball rebounds after each bounce
the percentage by which ball rebounds after each bounce= negative integer= k is negative integer.
Here are the answers for the HW:
Answer:
20
Step-by-step explanation:
n-50=30
n=-30+50
n+20