225.30816
Hope this helped :)))
9514 1404 393
Answer:
671 feet
Step-by-step explanation:
There are a couple of ways to figure this. One is to use a sort of shortcut equation to find the distance traveled (d) by an object when subject to some initial velocity (v) and acceleration (a). Here the acceleration due to gravity is -32 ft/s².
v² = 2ad
d = v²/(2a) = (192 ft/s)^2/(2·32 ft/s²) = 576 ft
This height is in addition to the starting height of 95 ft, so the arrow's maximum height is ...
max height = 95 ft + 576 ft = 671 ft
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Another way to work this problem is to start with the equation for ballistic motion. Filling in the given initial velocity and height, we have ...
h(t) = -16t^2 +192t +95
The time the arrow reaches the maximum height is the time representing the axis of symmetry of the parabola:
t = -(192)/(2(-16)) = 6
Then the maximum height is ...
h(6) = -16·6^2 +192·6 +95 = 671
The maximum height is 671 feet.
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<em>Additional comment</em>
For the standard-form quadratic ...
y = ax^2 +bx +c
The axis of symmetry is ...
x = -b/(2a)
Okay so here we have the function f(x)=3x-6 if you plug in -2 to x you get -12 if you plug in -1 you get -9 and if you plug in 0 you get -6 add three each time
No. See, you can take 60 out of 156 twice and you are left with 36. This means the drive would take about 2 hours and 36 minuets. 7+2=9 30+36=66 so then you add an our the time and you get that she would arrive a few minuets afterwards. (I'm sorry if I didn't explain this very well)
Answer:
$15.28 for 6 issues cost more
Step-by-step explanation:
$29.88 divided by 12 is $2.49
$15.28 divided by6 is $2.546