First list all the terms out.
e^ix = 1 + ix/1! + (ix)^2/2! + (ix)^3/3! ...
Then, we can expand them.
e^ix = 1 + ix/1! + i^2x^2/2! + i^3x^3/3!...
Then, we can use the rules of raising i to a power.
e^ix = 1 + ix - x^2/2! - ix^3/3!...
Then, we can sort all the real and imaginary terms.
e^ix = (1 - x^2/2!...) + i(x - x^3/3!...)
We can simplify this.
e^ix = cos x + i sin x
This is Euler's Formula.
What happens if we put in pi?
x = pi
e^i*pi = cos(pi) + i sin(pi)
cos(pi) = -1
i sin(pi) = 0
e^i*pi = -1 OR e^i*pi + 1 = 0
That is Euler's identity.
Answer:
x = -7
Step-by-step explanation:
Simplifying
5x + 130 = 8x + 151
Reorder the terms:
130 + 5x = 8x + 151
Reorder the terms:
130 + 5x = 151 + 8x
Solving
130 + 5x = 151 + 8x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-8x' to each side of the equation.
130 + 5x + -8x = 151 + 8x + -8x
Combine like terms: 5x + -8x = -3x
130 + -3x = 151 + 8x + -8x
Combine like terms: 8x + -8x = 0
130 + -3x = 151 + 0
130 + -3x = 151
Add '-130' to each side of the equation.
130 + -130 + -3x = 151 + -130
Combine like terms: 130 + -130 = 0
0 + -3x = 151 + -130
-3x = 151 + -130
Combine like terms: 151 + -130 = 21
-3x = 21
Divide each side by '-3'.
x = -7
Simplifying
Hello: here is a solution
Answer:
Step-by-step explanation:
The answer to this question is 3
Hope this helps
Answer:
c
Step-by-step explanation:
hope this helps
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