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adell [148]
3 years ago
15

An athlete ran 1,200 laps around a track over a two month period. He ran 4 times the number of laps in the second month than he

ran in the first month. How many laps did the athlete run in the first month?
Mathematics
1 answer:
Tema [17]3 years ago
3 0
Your answer should be 3600<span />
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I just took a screenshot of it, but I have no idea how to do this
Marianna [84]

Answer:

84°

Step-by-step explanation:

Solve for n. Note that the angle measurements of a circle will equal 360°. Set all the angles = 360°.

7n + 12 + 13n - 16 + 6n = 360

Combine like terms:

(7n + 13n + 6n) + (12 - 16) = 360

26n - 4 = 360

Isolate the variable, n. Note the equal sign, what you do to one side, you do to the other. First, add 4 to both sides:

26n -4 (+4) = 360 (+4)

26n = 360 + 4

26n = 364

Next, divide 26 from both sides:

(26n)/26 = (364)/26

n = 364/26

n = 14

Next, plug in 14 for n in the angle measurement, 6n:

6n = 6(14) = 84°

Note that these are central angles, which means that the arc's will be the same measurement as the angle's measurement.

arcBC = 84°

84° is your answer.

~

3 0
3 years ago
Pls show work! questions on pic
Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

x\geq 5

y\geq 20

Perimeter of rectangle=2(x+y)

Where x=Width  of rectangle

y=Length of rectangle

Fencing used =2(x+y)

2(x+y)\leq 80

First we change inequality  into equality

x=5...(1)

y=20...(2)

2(x+y)=80

x+y=40...(3)

Substitute x=0 in equation (3)

y=40

Substitute y=0  in equation (3)

x=40

Substitute x=0 and y=0 in equation (3)

2(x+y)\leq 80

0\leq 80

It is true. Therefore, the  shaded region below the line.

0\geq 5

0\geq 20

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

5+y=40

y=40-5=35

Substitute y=20 in equation (3)

x+20=40

x=40-20=20

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

2(x+y)\leq 80

2(10+23)\leq 80

66\geq 80

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

2(7+30)=74

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

2(18+25)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

2(8+35)=86>80

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

2(20+20)=80

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0
3 years ago
Which ratio froms a proportional with 16/20? A 4/10 B 32/50 C 8/12 D 4/5​
kiruha [24]
D . 4/5 16/4 = 4 | 20/4=5.
6 0
3 years ago
Read 2 more answers
(I need help)
natima [27]

Answer:

b. 9

Step-by-step explanation:

36+97=133

80+44=124

133-124=9

4 0
3 years ago
274,635 rounded to the nearest thousands
Firlakuza [10]

275000 is your answer

hope it help

6 0
2 years ago
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