Answer:
Step-by-step explanation:
1.
cot x sec⁴ x = cot x+2 tan x +tan³x
L.H.S = cot x sec⁴x
=cot x (sec²x)²
=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]
= cot x(1+ 2 tan²x +tan⁴x)
=cot x+ 2 cot x tan²x+cot x tan⁴x
=cot x +2 tan x + tan³x [ ∵cot x tan x
=1]
=R.H.S
2.
(sin x)(tan x cos x - cot x cos x)=1-2 cos²x
L.H.S =(sin x)(tan x cos x - cot x cos x)
= sin x tan x cos x - sin x cot x cos x

= sin²x -cos²x
=1-cos²x-cos²x
=1-2 cos²x
=R.H.S
3.
1+ sec²x sin²x =sec²x
L.H.S =1+ sec²x sin²x
=
[
]
=1+tan²x ![[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Ctextrm%7Bsin%20x%7D%7D%7B%5Ctextrm%7Bcos%20x%7D%7D%20%3D%20%5Ctextrm%7Btan%20x%7D%5D)
=sec²x
=R.H.S
4.

L.H.S=



= 2 csc x
= R.H.S
5.
-tan²x + sec²x=1
L.H.S=-tan²x + sec²x
= sec²x-tan²x
=


=1
Answer:
<em>(-2)2 - (-8) + 1</em>
Step-by-step explanation:
When you substitute values into an algebraic equation, you need to input the values exactly how they are given. "w" must go where there are "w"s, and "v" must go where the "v"s are, otherwise you will get an incorrect answer. All values must also carry over their signs--they are one unit--and must be inserted as such, which is why - (-8) is correct, but not - (8) or - 8. (This is because those two negatives will cancel each other out and become +8 when solving). The parenthesis around the values are important because they protect the original values of the variables, which is why (-2)2 is correct. In the case of (-2)2, it also signifies that they are "attached" by multiplication, and when solving would become -4. Without signifying that the variables are separate from the rest of the equation via the parenthesis, it becomes very easy to solve it incorrectly.
Is means =
less than is subtract
1/2a -8=2
if you need to know how to do it let me know
The remainder is or answer is 6
Answer:

So then the difference between the two proportions is 0.045 and if we convert this into % we got

Step-by-step explanation:
For this case we can define the following notation:
represent the unemployment rate for high school graduates with no college degree
represent the unemployment rate for college graduates with a bachelor's degree
And for this case we need to find the difference in proportions of those unemployed between these two groups, we want to find:

From the info given we have 

And the difference:

So then the difference between the two proportions is 0.045 and if we convert this into % we got
