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-Dominant- [34]

2 years ago

10

Father's age is 3 times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children

. Find the age of father.

1 answer:

ra1l [238]2 years ago

7 0

Answer:

45 is the father's age

Step-by-step explanation:

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Pls answer this with an explanation if you can pg3 pt12

faust18 [17]

With each gallon you need 11 gallons with 2 parts red 9 parts yellow and since 11x4= 44 you need to do this 4 times
4x2(red)= 8
4x9(yellow)=36
36+8=44
basically 8 gallons of red
i hope this made sense

7 0

3 years ago

mary wants to fill in a cylinder vase. the flower store told her to fill the vase 4/5 of the way for the flowers to last the lon

Goshia [24]

Volume is a three-dimensional scalar quantity. The volume of the water that Marry should pour into the vase is 241.28 cubic inches.

<h3>What is volume?</h3>

A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.

Given the radius of the flower vase is 4 inches, while the height of the vase is 6 inches, therefore, the total volume of the vase is,

Volume = πR²×H = π× 4²×6 = 301.6 in³

Since the volume of the vase is 301.6 in³, but the store has told her to fill the vase 4/5 of its capacity, therefore, the volume of water Marry should pour is,

Volume of water = (4/5) × 301.6 in³ = 241.28 cubic inches

Hence, the volume of the water that Marry should pour into the vase is 241.28 cubic inches.

Learn more about Volume:

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4 0

1 year ago

Help! this is in algebra 1

Scrat [10]

Answer: I have the pictures attached

Step-by-step explanation:

In order to graph this, we have to get it into this equation: y = mx + b, where m = slope and b = y intercept.

y = 3/2x - 4 is already in this form.

2y + 4 = 2 + 3x is not, so we have to isolate y

2y + 4 - 4 = 2 + 3x - 4

2y = -2 + 3x

2y/2 = -2/2 + 3x/2

y = -1 + 3/2x

y = 3/2x - 1

Okay, now graph it knowing your y intercepts and your slopes.

7 0

3 years ago

What is 5 1/4 - 3 3/8<br> In a fraction

Maksim231197 [3]

First, turn the fractions into mixed numbers.

21/4 - 27/8

Then. make the denominators the same.

4 * 2 = 8

21 * 2 = 42

42/8 - 27/8

42 - 27 = 15

15/8

15/8 = 1 7/8

3 0

3 years ago

Perform the following operations s and prove closure. Show your work.

nadezda [96]

Answer:

1. $\frac{x}{x+3}+\frac{x+2}{x+5}$ = $\frac{2x^2+10x+6}{(x+3)(x+5)}\\$

2. $\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}$ = $\frac{1}{(x+2)(x-4)}$

3. $\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}$ = $\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}$

4. $\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}$ = $\frac{1}{(x-2)(x-4)}$

Step-by-step explanation:

1. $\frac{x}{x+3}+\frac{x+2}{x+5}$

Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

$=\frac{x(x+5)+(x+2)(x+3)}{(x+3)(x+5)}\\=\frac{x^2+5x+(x)(x+3)+2(x+3)}{(x+3)(x+5)} \\=\frac{x^2+5x+x^2+3x+2x+6}{(x+3)(x+5)} \\=\frac{x^2+x^2+5x+3x+2x+6}{(x+3)(x+5)} \\=\frac{2x^2+10x+6}{(x+3)(x+5)}\\$

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.

2. $\frac{x+4}{x^2+5x+6}*\frac{x+3}{x^2-16}$

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)

Putting factors

$=\frac{x+4}{(x+3)(x+2)}*\frac{x+3}{(x-4)(x+4)}\\\\=\frac{1}{(x+2)(x-4)}$

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.

3. $\frac{2}{x^2-9}-\frac{3x}{x^2-5x+6}$

Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)

Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)

Putting factors

$\frac{2}{(x+3)(x-3)}-\frac{3x}{(x+3)(x-2)}$

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)

$\frac{2(x-2)-3x(x+3)(x-3)}{(x+3)(x-3)(x-2)}$

$=\frac{2(x-2)-3x(x+3)}{(x+3)(x-3)(x-2)}\\=\frac{2x-4-3x^2-9x}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-9x+2x-4}{(x+3)(x-3)(x-2)}\\=\frac{-3x^2-7x-4}{(x+3)(x-3)(x-2)}$

Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.

4. $\frac{x+4}{x^2-5x+6}\div\frac{x^2-16}{x+3}$

Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)

Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

$\frac{x+4}{(x-2)(x+3)}\div\frac{(x-4)(x+4)}{x+3}$

Converting ÷ sign into multiplication we will take reciprocal of the second term

$=\frac{x+4}{(x-2)(x+3)}*\frac{x+3}{(x-4)(x+4)}\\=\frac{1}{(x-2)(x-4)}$

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.

5 0

3 years ago