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ruslelena [56]
4 years ago
14

Is Salt and pepper an example of a homogenous mixture?

Chemistry
1 answer:
alisha [4.7K]4 years ago
4 0

Answer:

no it is a heterogeneous mixture because salt and pepper are not mixed uniformly.

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6 0
3 years ago
What are Intensive and Extensive properties?
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Intensive properties are the properties which values doesnt change with the amount of mass or material that you have, example density, melting point boiling point, molecular mass

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mass, volume, quantity (there is only one of each), color, reflect light, temperature, energy
5 0
3 years ago
What steps have power plants taken to reduce the amount of sulfur oxides released into the air?
Ann [662]
Emissions of SO2 generated during the combustion of fossil fuels can be reduced<span> by treating the flue gases before they are emitted into the atmosphere via the stack; this is termed Flue Gas Desulphurisation (FGD). Flue gas desulphurisation systems can be classified as either Regenerable or Non-regenerable.

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5 0
3 years ago
6 NaOH + 2 Al --&gt; 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?
tatyana61 [14]

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of Na_3AlO_3.

So, 1 mole of Al produce 1 mole of  Na_3AlO_3.     .....statement 1)

Number of moles of Al in 258 gram of Al.

n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles

Therefore, from statement 1) number of moles of Na_3AlO_3 produced is also 9.556 moles.

7 0
3 years ago
Will the volume of a 1.0 L sample of gas at STP change if the pressure and temperature are both doubled
Dmitry_Shevchenko [17]

Answer:

The volume will not change.  This belongs in Ripley's Believe It or Not.

Explanation:

The combined gas law can be used to model both the initial (1) and ending (2) states of a gas when pressure (P), temperature (T) and/or volume (V) change, but the number of moles does not.  Remember that temperature must always be in Kelvin.

P1V1/T1 = P2T2/T2

Rearranging for V2:

V2 = V1(T2/T1)(P1/P2)

I've arranged the pressure and temperature terms as ratios.  This makes it easier to see what impact changes will have, plus the units conveniently cancel for both.

(V2) = (1 L)(T2/T1)(P1/P2)

We are told that P2 and T2 are both doubled:

   (T2/T1) = 2

   (P1/P2) = 1/2

V2 = (1 L)(T2/T1)(P1/P2)

V2 = (1 L)(2)(1/2)

V2 = (1 L)(2)(1/2)

V2 - 1 L

The volume does not change.  Bummer.

7 0
2 years ago
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