Question

6 NaOH + 2 Al --> 2 Na3AlO3 + 3 H2 If you start with 258 g of Al, how many moles of Na3AlO3 can you make?

Answer 1

Solution :

Assuming all Al will be consumed in the reaction.

From the given equation, 2 mole of Al produce 2 mole of $Na_3AlO_3$.

So, 1 mole of Al produce 1 mole of  $Na_3AlO_3$.     .....statement 1)

Number of moles of Al in 258 gram of Al.

$n = \dfrac{mass}{molar\ mass}\\\\n = \dfrac{258}{27}\ moles\\\\n = 9.556 \ moles$

Therefore, from statement 1) number of moles of $Na_3AlO_3$ produced is also 9.556 moles.