Answer: Option d. pressure increase by a factor of 3
Explanation:
P1 = P
T1 = 300k
T2 = 900K
P2 =?
Volume is constant.
P1/T1 = P2/T2
P/300 = P2/900
P2 x 300 = P x 900
P2 = (P x 900)/300
P2 = 3P
The pressure increased by a factor of 3
Answer:
506.912 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of O₂ = 22.63 moles
Volume of O₂ =?
Recall:
1 mole of a gas occupy 22.4 L at STP.
With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.
Thus, 22.63 moles of O₂ is equivalent to 506.912 L.
Answer:
D. Exothermic.
Explanation:
Hello there!
In this case, since the potential energy versus reaction progress diagrams are related to the energetic profile of a chemical reaction, we can set the initial point at the beginning of the reaction as the energy of the reactants and the final point as the energy of the products.
Next, since the change in the enthalpy of a reaction is quantified by subtracting products minus reactants, we can see that the products have less energy than the reactants and therefore ΔH for this reaction is negative, which matches with the definition of D. Exothermic reaction.
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Answer:a lightbulb burning
Explanation:
Apex
Answer:
V=?
S=25m
t=2.5s
V=S/t
V=25/2.5
V=10m/s
So, the ball was traveling with the speed of 10m/s.