Answer:
The answer is
Step-by-step explanation:
If two equations are parallel it means that both their gradients are equal. We were given the equation:
in order to find the gradient of this equation that we are given we have to ensure that it is in its simplest form:
Therefore the gradient of the parallel line with points (-2, 4) is also -5/2
Answer:
Horizontal shift:
For the parent function f(x) and a constant h, the function given by g(x) = f(x-h) can be sketched by shifting f(x) h units horizontally.
The values of h determines the direction of shifts:
If :
- h>0, the parent graph shifts h units to the right
- h < 0, the parent graph shifts h units to the left.
Vertical shifts:
For the parent function f(x) and a constant k, the function given by g(x) =f(x) +k can be sketched by shifting f(x) k units vertically.
The value of k determines the direction of shifts;
if:
-
k > 0, the parent graph shifts k units upward, and
- k < 0, the parent graph shifts k units downward.
Therefore, the values of h and k in y=|x-h|+k affect the graph of y=|x| tells us how far the graph shifts horizontally and vertically.
Answer:
<h2>Option A, C and D is the three possible solution.</h2>
Step-by-step explanation:
Each Television earns $72 and each Computer earns $90.
The manager’s target is to make at least $360.00 a day.
It is <u>not clarified the exact number of Televisions and Computers</u>.
Hence, as per the given condition, 
.
Now we just need to check the given options, whether they satisfy the above equation, or not.
Except the option B, each inequality indicates a value greater than 360.
Hence, option B can not be the possible solution.
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
