Answer:
The factors of x² - 3·x - 18, are;
(x - 6), (x + 3)
Step-by-step explanation:
The given quadratic expression is presented as follows;
x² - 3·x - 18
To factorize the given expression, we look for two numbers, which are the constant terms in the factors, such that the sum of the numbers is -3, while the product of the numbers is -18
By examination, we have the numbers -6, and 3, which gives;
-6 + 3 = -3
-6 × 3 = -18
Therefore, we can write;
x² - 3·x - 18 = (x - 6) × (x + 3)
Which gives;
(x - 6) × (x + 3) = x² + 3·x - 6·x - 18 = x² - 3·x - 18
Therefore, the factors of the expression, x² - 3·x - 18, are (x - 6) and (x + 3)
u = 9 i - 6 j
v = -3 i - 2j
w = 19 i + 15 j
u • v = (9 i - 6 j) • (-3 i - 2j)
Distribute the dot products:
u • v = 9*(-3) (i • i) + 9*(-2) (i • j) + (-6)*(-3) (j • i) + (-6)*(-2) (j • j)
i and j are orthogonal unit vectors, so their dot products are 0, while i • i = j • j = 1. So we have
u • v = 9*(-3) + (-6)*(-2) = -27 + 12 = -15
In other words, the dot product can be computed by simply multiplying corresponding components, and taking the total.
u • w = 9*19 + (-6)*15 = 81
True,
considering the definition of slope is "rise over run"
the rise would be infinite whereas the run would be zero
so the result would be infinity over zero.
problem is, you cant multiply by infinity nor can you divide by zero, hence its undefined
Answer:
3 + 5n
Step-by-step explanation:
This is an arithmetic sequence.
First term = a = 8
Common difference = d =Second term - first term
= 13 - 8
= 5
Nth term = a + (n- 1)*d
= 8 + (n -1) * 5
= 8 + n*5 - 1 *5
= 8 + 5n - 5
= 8 - 5 + 5n
= 3 + 5n
Answer:
f(x) → -∞ as x → -∞
f(x) → -∞ as x → +∞
Step-by-step explanation:
The given function is;
f(x) = -5x^(6) + 8x^(5) - 1/(x² - 9x)
Using long division to divide this as attached, we have;
f(x) = -5x⁴ - 37x³ - 333x² - 2997x - 26973 + (-242757x - 1)/(x² - 9x)
Thus, the leading coefficient here is -5 and the polynomial degree is 4.
Since the leading coefficient is negative and the degree of the polynomial is an even number, then we can say that the behavior of the polynomial is;
f(x) → -∞ as x → -∞
f(x) → -∞ as x → +∞