Ask question

Ask question

All categories

3 years ago

6

In Exercise,solve for 0 < x - 5

1 answer:

uysha [10]3 years ago

3 0

Answer:

x > 5

Step-by-step explanation:

0 < x-5. Add 5 to both sides...

+5 +5

5 < x Rearrange answer

x > 5

You might be interested in

Find f(-3) for f(x) = 4(2)^x.<br> ОА. 1/8<br> O B. -32<br> O C. -24<br> OD. 1/2

Ipatiy [6.2K]

Answer:

D

Step-by-step explanation:

using the rule of exponents

$a^{-m}$ = $\frac{1}{a^{m} }$

substitute x = - 3 into f(x)

f(- 3) = 4( $(2)^{-3}$ = 4 × $\frac{1}{2^{3} }$ = 4 × $\frac{1}{8}$ = $\frac{1}{2}$

5 0

2 years ago

A cell tower is located at and transmits a circular signal that covers three major cities. The three cities are located on the c

Lelu [443]

Answer:

$(x+8)^2 +(y-4)^2 = 25$

Step-by-step explanation:

Assuming this complete problem: "A cell tower is located at (-8, 4) and transmits a circular signal that covers three major cities. The three cities are located on the circle and have the following coordinates: G (-4, 7), H (-13, 4), and I (-8, -1). Find the equation of the circle"

For this case the generla equation for the circle is given by:

$(x-h)^2 +(y-k)^2 = r^2$

From the info we know that the tower is located at (-8, 4) so then h = -8 and k = 4, so then we need to find the radius. So we have the equation like this: $(x+8)^2 +(y-4)^2 = r^2$

If the 3 points are on the circle then satisfy the equation. We can use the first point (-4,7) and if we replace we can find the value for $r^2$

$(-4+8)^2 +(7-4)^2 =25= r^2$

So then $r = \sqrt{25}=5$

And if we replace the second point we got this:

$(-13+8)^2 +(4-4)^2 = 25 =r^2$

And for the third point we have:

$(-8+8)^2 +(-1-4)^2 = 25 =r^2$

And we got the same result.

So then our final equation is given:

$(x+8)^2 +(y-4)^2 = 25$

4 0

3 years ago

Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2

Phoenix [80]

Answer:

B

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = $\sqrt{3}$ , then letting the altitude be h

tan60° = $\frac{opposite}{adjacent}$ = $\frac{11\sqrt{6} }{h}$ = $\sqrt{3}$ ( multiply both sides by h )

11 $\sqrt{6}$ = h × $\sqrt{3}$ ( divide both sides by $\sqrt{3}$ )

11 $\sqrt{2}$ = h

using the sine ratio in the triangle on the left and the exact value

sin45° = $\frac{\sqrt{2} }{2}$ , then

sin45° = $\frac{opposite}{hypotenuse}$ = $\frac{h}{x}$ = $\frac{11\sqrt{2} }{x}$ = $\frac{\sqrt{2} }{2}$ ( cross- multiply )

$\sqrt{2}$ × x = 22 $\sqrt{2}$ ( divide both sides by $\sqrt{2}$ )

x = 22

6 0

1 year ago

A farmer has enough feed to last his 15pigs for 20days. How long would the feed last if he had 10pigs

ddd [48]

40/3 days, (13.33 days)

Step-by-step explanation:

Set up the equation, 15/20 = 10/x, and then use cross mutiply to solve it.

10 * 20 = 15x, x = 200/15 = 40/3

Why?

b/c if each pig eats the same amount of food, then the ratio between the number of pigs and days should remain constant.

5 0

2 years ago

In 1970 there were estimated to be around 40,000 Bengal Tigers in the world. The population of Bengal Tigers decreased by an ave

NISA [10]

Answer:

Step-by-step explanation:

y = (40000)0.95^t

t = time in years

4 0

3 years ago

Read 2 more answers