Can someone possibly help me with this math question?

Mathematics

1 answer:

MariettaO [177]2 years ago

3 0

Answer:

its 4

Step-by-step explanation:

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Please help, only the answer is required

Romashka [77]

Answer:

Infinitely many solutions.

Step-by-step explanation:

5x-8y=-11

-10x+16y=22

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2(5x-8y)=2(-11)

-10x+16y=22

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10x-16y=-22

-10x+16y=22

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0+0=0

infinitely many solutions

6 0

2 years ago

Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2

zaharov [31]

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290

6 0

2 years ago

Sin5A/SinA-cos5A/cosA=4cos2A

irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

$\frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved$