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3 years ago

How does a digit in the ten thousands place compare to a digit in the thousands place ?

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Ten thousands place is 10 times bigger than thousands place

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What is (27/8)^-2/3 ?

Paraphin [41]

Answer:

Step-by-step explanation:

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3 years ago

Find the difference using the number line!!!!!!!!!!!!! Help

Rzqust [24]

The correct answer is 7.2

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3 years ago

In a sample of 75 randomly selected students at school, 32 are female. There are 1, 371 students in the school. Using these resu

netineya [11]

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3 years ago

use the substitution method to slove the system of equations choose the correct ordered pair x+y=11 -x=-y-10

lara31 [8.8K]

Answer:

(10, 1)

Step-by-step explanation:

-x = -y - 9 has already been solved for -x. Multiply every term of this equation by -1 to obtain x = y + 9.

Now substitute y + 9 for x in the first equation. We get:

(y + 9) + y = 11, or, after combining the y terms, 2y = 2.

Solving for y, we get y = 1.

Subbing 1 for y in the first equation results in: x + 1 = 11.

This yields x = 10.

Thus, the solution is (10, 1).

3 0

3 years ago

A species of animal is discovered on an island. Suppose that the population size P(t) of the species can be modeled by the follo

Ilya [14]

Answer:

The initial population is 200

The population after 10 years is 687

Step-by-step explanation:

Given

$P(t) =\frac{800}{1+ 3e^{-0.29t.}}$

Solving (a): The initial population

Here:

$t = 0$

Substitute 0 for t in P(t)

$P(0) =\frac{800}{1+ 3e^{-0.29*0}}$

$P(0) =\frac{800}{1+ 3e^{0}}$

$P(0) =\frac{800}{1+ 3*1}$

$P(0) =\frac{800}{1+ 3}$

$P(0) =\frac{800}{4}$

$P(0) =200$

The initial population is 200

Solving (b): Population after 10 years.

Here

$t = 10$

Substitute 10 for t in P(t)

$P(10) =\frac{800}{1+ 3e^{-0.29*10}}$

$P(10) =\frac{800}{1+ 3e^{-2.9}}$

$P(10) =\frac{800}{1+ 3*0.055}$

$P(10) =\frac{800}{1+ 0.165}$

$P(10) =\frac{800}{1.165}$

$P(10) =687$ -- approximated.

The population after 10 years is 687

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3 years ago