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2 years ago

Compound interest

Mathematics

1 answer:

aev [14]2 years ago

3 0

9514 1404 393

Answer:

4254.31

Step-by-step explanation:

The compound interest multiplier is ...

m = (1 +r/n)^(nt) . . . . annual rate r compounded n times per year, t years

For 11% compounded quarterly for 18 years, the multiplier is ...

m = (1 +0.11/4)^(4·18) = 1.0275^72 ≈ 7.0516671

If 30,000 is the future value, then the present value is ...

PV = FV/m = 30,000/7.0516671

PV ≈ 4254.31

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In parallelogram ABCD, AB = 16 cm, DA = 3<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%7D" id="TexFormula1" title="\sqrt{2}" alt

Murljashka [212]

Answer:

length of segment YZ is 8 cm

Step-by-step explanation:

given data

AB = 16 cm

DA = 3 $\sqrt{2}$ cm

AB and DA form interior angle = 45-degre

WX ≠ YZ

WX = 16 cm

to find out

length of segment YZ

solution

area of △ABD is the same as the area of △BCD

and

area of △ABD is express as

area of △ABD = AB × AD × sin(45) ÷ 2 ............1

put here value

area of △ABD = 16 × 3√2 × sin(45) ÷ 2

area of △ABD = 24

and

area of the parallelogram is

area of the parallelogram = 24 × 2

area of the parallelogram = 48

now we will consider here YZ = x

and Since ZY XW is isosceles trapezoid

so here we can say that

WM = ZM = (16 - x) ÷ 2 .......................2

so area of trapezoid will be

area of trapezoid = $\frac{ZY + WX }{2} \times ZM$ .......................3

area of trapezoid = $\frac{x+16}{2} \times \frac{16 - x}{2}$

48 = $\frac{x+16}{2} \times \frac{16 - x}{2}$

solve it we get

x = 8

so length of segment YZ is 8 cm

7 0

3 years ago

WILL MARK BRAINLEIST PLZ HELP

Dmitry [639]

Answer:

Step-by-step explanation:

The scale factor is 3.5 which is found out by doing 14 divided by 4. Once you know the scale factor you simply have to do 8 multiplied 3.5 which equals 28.

8 0

3 years ago

Convert 12.4 hours to hours and minutes.

Katen [24]

Answer:

12.4=12 hours and 24 minutes

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The speed of light is estimated at 186,000 miles per second rounded to the nearest thousand miles per second.

4vir4ik [10]

It was rounding to the nearest THOUSAND.

We are looking at the thousands place, keep that in mind.

Remember: everything 5 and above is rounded up, everything below 5 is rounded down.

186,789 is above 500, it is rounded to 187,000

186,899 is above 500, it is rounded to 187,000

185,990 is above 500, it is rounded to 186,000

and 185,190 is below 500, it is rounded to 185,000

Only one matches the criteria of the question:

185,990 is above 500, it is rounded to 186,000

therefore the answer is 185,990 miles per second

Have a fantastic day!

7 0

3 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

3 years ago