Answer:
Classification
Explanation:
Building a machine learning solution that can predict the success of a student in completing a college degree is a binary problem. There are two possible answer: success or not success.
This brings us to a supervised machine learning problem, where one trains the technique with labeled data whether it is a success or not. Since the target variable is discrete (not continuous), classification technique has to be used.
A. Assets increase, and liabilities decrease.
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
Answer:
down below
Explanation:
score = input() # gets student's score input
max = input() # gets max number
percent = (score/max)*100 # multiply by a hundred to get percentage
if percent > 52: # checks if percent is greater than 52
print("well dont you have at least a grade 5")
else # if percent is less than or equal to 52 it will print this instead
print("Unlucky, you need to revise more for the next test.")
THIS PART IS NOT CODE:
make sure you indent/tab the print statements or else you'll get an error
