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Fynjy0 [20]
3 years ago
6

The figure below is a diagram of a trapezoidal table that needs to be stained. Each can of stain will cover 50 square inches.

Mathematics
1 answer:
Soloha48 [4]3 years ago
6 0

Each can of stain covers 50 square inches.

Hence, we need 7 cans of stain to cover at least 324 square inches.

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Without multiplying, tell which is greater: 4/5 x 45 or 2/3 x 45. Explain.
Aloiza [94]

Answer: It is 4/5 x 45

Step-by-step explanation: Hope i helped please mark brainliest!

I know there is suppose to be no multiplying but if you mulitply in your head 4/5 x 45 is 36 and 2/3 x 45 is 30

therefore, 4/5 x 45 is greater!

also, if not multiplying 0.8(5/4) is greater than 0.667(2/3). Therefore, 4/5 is greater than 2/3.

3 0
4 years ago
What is f(4) for the graph shown below?
Snowcat [4.5K]

Answer:

f(4)= 1

Step-by-step explanation:

f(x) = y

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3 0
3 years ago
I need help I never got taught how to do this
ludmilkaskok [199]

Answer:

736cm²

Step-by-step explanation:

The surface area of a regular pyramid is equal to:

area of the square base + 1/2ps

where p is the perimeter of the base and

s is the height of the slant line of the pyramid.

In your drawing s = 15cm and the base has four equal lengths of 16cm

So first find the area of the base.  Since this is a square, the area is just the

length x the width or 16cm x 16cm = 256cm²

(p) is the perimeter of the base.  Find this by adding all four side of the bottom square together which is 16cm + 16cm + 16cm + 16cm  or  4 x 16cm which is 64cm.

You already were given (s) which is the height of the slanted side from the base to the pointed top.  The drawing gives you this as 15cm.

So plugging all this into the formula, you get:

Surface Area = Area of Base + 1/2 p s

                      =  256 cm² + [1/2 ( 64cm )(15cm)]

                      =  256 cm²  +  {1/2 ( 960 cm²)]

                      =  256 cm²  +  480 cm²

                      =  736 cm²

8 0
3 years ago
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3c = 12.69
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3 years ago
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yanalaym [24]
There is not enough information to solve the question
8 0
3 years ago
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