The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
54318
Step-by-step explanation:
my teacher told me the numbers are 54,3 and 18
Answer:
There are two x-intercepts.
A quadratic function whose maximum degree two. Therefore, Total two x-intercept possible.
We are given the range of quadratic function y less than equal to 2. It means parabola is downward whose maximum value 2.
Here y is greater than 2 and parabola form downward. Here must be two x-intercept.
If a>0 then form open up parabola.
If a<0 then open down parabola.
Here open down parabola. So, we get total two x-intercept.
Please see the attachment for diagram.
Answer:
second and last are true
Step-by-step explanation: