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Vikentia [17]
3 years ago
12

Joe wants to enlarge the rectangular pumpkin patch located on his farm. The pumpkin patch is currently 40 meters wide and 60 met

ers long. The new pumpkin patch will be 3x meters wider and 5x meters longer than that of the original pumpkin patch. Which of the following functions will give the area of the new pumpkin patch in square meters?

Mathematics
1 answer:
vodomira [7]3 years ago
5 0

Answer:

15x^2+380x+2400

The diagram is shown below for reference.

Step-by-step explanation:

We are given the length and width of old pumpkin patch as 60 meters and 40 meters respectively.

It further says length is increased by 5x meters and width increased by 5x meters.

So the length of the new pumpkin patch would be 60+5x meters.

And the width would be 40+3x meters.

We know area of a rectangular shape =length \times width

So, plugging the above values, we get the area of the new pumpkin patch as:

=(60+5x)\times (40+3x)\\=2400+180x+200x+15x^2\\=2400+380x+15x^2\\=15x^2+380x+2400 on rearranging.

Thus the function of the area of the new pumpkin patch would be:

f(x) = 15x^2+380x+2400

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<h2>Answer:</h2>

The number is -2.

<h2>Step-by-step explanation:</h2><h3>Written out, our equation looks like this:</h3><h3>(-5·x)+2=12</h3>

We'll start of by taking our final result of 12 and subtracting 2, as the beginning of the statement says "two more."

<h3>12 minus 2 gives us 10.</h3>

Now, since the statement says "the product of -5," we will take this 10 and divide by -5.

<h3>10 divided by -5 gives us -2.</h3>

This means that our number, x equals -2. Of course, we must input this solution to double check our work.

<h3>(-5·<u>-2</u>)+2=12</h3><h3>10+2=12</h3><h3>12=12</h3>

<h2>Our final answer is x=-2!</h2>
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