pretty much about the same as before.
a = weight of a large box
b = weight of a small box.
we know their combined weight is 65 lbs, thus a + b = 65.
we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

Big ifs, question writers. These are of course approximations.
The "co" in cosine comes from complementary angles. It means since


Answer: cos 48° = 2/3
Similarly,


Answer: tan 69.5° = 8/3
5x + 3. You can also synthetically divide because of the linear divisor
You have to replace d woth 3 in formula
7d^2+10=7*(3)^2+10=7*9+10=63+10=73
d is the correct answer
Answer:
90°
Step-by-step explanation:
sample answer given on edge