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MariettaO [177]
4 years ago
7

Can you help me with this please?

Mathematics
1 answer:
N76 [4]4 years ago
8 0
Use a calculator and divide
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A circle has radius of 18 cm. Find the area of the smaller of the two regions determined by a chord with length of 18√2 cm . Hin
boyakko [2]
The area is 81*pi-162. Look at the triangle formed by the chord and the two radii connected to the endpoints of the chord. Since 18^2+18^2=(18*\sqrt2)^2, this is an isosceles right triangle by Pythagorean theorem. The area of the quarter circle containing the region we look for is pi*18^2/4=81*pi. The area of the right triangle is 18*18/2=162. The difference between these two areas, or 81*pi-162, is the area of the smaller region.
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3 years ago
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4 years ago
amin is using a hose to fill his new pool for the first time. he starts the hose at 10 pm and leaves it running all night. at 6
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3 years ago
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Alex777 [14]
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4 years ago
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nignag [31]
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