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MariettaO [177]
3 years ago
7

Can you help me with this please?

Mathematics
1 answer:
N76 [4]3 years ago
8 0
Use a calculator and divide
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2/3=x/6=9/y to find the value of y in this proportion you must divide 54 by
scZoUnD [109]

Answer:

You must divide 54 by 4

Step-by-step explanation:

we have

\frac{2}{3}=\frac{x}{6}=\frac{9}{y}

Step 1

Solve for x

\frac{2}{3}=\frac{x}{6}

3x=6*2\\x=12/3\\x=4

Step 2

Find the value of y

\frac{x}{6}=\frac{9}{y}

Substitute the value of x

\frac{4}{6}=\frac{9}{y}

4y=9*6\\y=54/4\\y= 13.5

therefore

You must divide 54 by 4

6 0
3 years ago
Read 2 more answers
1/2x+5=1/3x what do you multiply the equation by in order to get rid of the fractions in the problem
earnstyle [38]

Answer:

we should multiply by 6 to get rid of the fractions in problem

6 0
3 years ago
I POSTED THIS 3 TIMES AND NOBODY HELPED ME STILL?? :((( PLS HELP
Ipatiy [6.2K]

Answer:

the first one

Step-by-step explanation:

angle L congruent to angle P

4 0
3 years ago
There is a clown's face on the top of a spinner. The tip of his hat rotates to (−2, 5) during one spin. What is the cosine value
uranmaximum [27]
Remark
The point value is (-2,5) So we know the two sides. We need the hypotenuse. We should notice that the x value is minus (-2) and value is y value is plus (5). That means we are in quad 2. Be careful how you read that. (-2,5) is a point. It is not a tangent.

Step One 
Find the hypotenuse.

a = - 2
b = 5
c =  ??

c^2 = a^2 + b^2
c^2 = (-2)^2 + 5^2
c^2 = 4 + 25
c^2 = 29               Take the square root of both sides.
sqrt(c^2) = sqrt(29)
c = sqrt(29)

Step Two
Find the Cosine of the angle.
Cosine(theta) = adjacent / hypotenuse
Cosine(theta) = -2 / sqrt(29)  <<<<<<< Answer

Again, watch out for what you are given.
6 0
3 years ago
An elliptical culvert is 3.5 feet tall and 6 feet wide. It is filled with water to a depth of 0.95 feet. Find the width of the s
maks197457 [2]

Answer:

W_s \approx5.3

Step-by-step explanation:

From the question we are told that

Height H=3.5ft

Weight W= 6ft

Depth  D=0.95ft

Generally the equation for ellipses is given as

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

Where

b=H/2\\b=3.5/2\\Therefore\\b=1.75\\a=W/2\\a=6/2\\Therefore\\a=3\\

\frac{x^2}{3^2} +\frac{y^2}{1.75^2} =1

Generally to find y in the equation \frac{x^2}{a^2} +\frac{y^2}{b^2} =1

y=-b+d

y=-1.75+0.95

y=-0.8

Therefore

\frac{x^2}{3^2} +\frac{(0.8)^2}{1.75^2} =1

\frac{x^2}{3^2} =1-\frac{(0.8)^2}{1.75^2}

\frac{x^2}{3^2} =1-0.2089795918

X^2 =3^2(1-0.2089795918)

X^2 =7.119183674

X =\sqrt{7.119183674}

X =2.66817984

Therefore the width of the given stream is

W_s=2.66817984*2

W_s=5.33635968

W_s \approx5.3

3 0
3 years ago
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