Use the sum of cubes identity to find the factors of the expression
1 answer:
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$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$
Answer:
see explanation
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
(x + 4)² + (y + 6)² = 16 is in this form
with r² = 16 ⇒ r = = 4
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given (h, k) = (5, 2) and r = 20, then
(x - 5)² + (y - 2)² = 400 ← represents the delivery area