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Gala2k [10]
3 years ago
6

15 - 12 indicated operation

Mathematics
1 answer:
Rashid [163]3 years ago
6 0

Answer: 3

Step-by-step explanation:

12+3 =15

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The congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. The pe
Readme [11.4K]

Answer:

10 units

Step-by-step explanation:

Let the shortest side be x

Now since we are given that The congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle.

So, the length of the congruent sides (each) = x+1

Thus the perimeter of triangle = sum of all sides

                                                = x+x+1+x+1

                                                =3x+2

Now we are given that  The perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.

Side of square = x-2

So, perimeter of square = 4*side

                                        =4(x-2)

                                        =4x-8

Now since the perimeter of the triangle and square are equal

So,3x+2=4x-8

10=x

Hence the shortest side of the triangle is 10 units.

5 0
4 years ago
Read 2 more answers
What number should be added by both sides of the equation to complete the the square?<br> x^2-10x=7
NemiM [27]
You add 25 to both sides.
You take half the x term, which is 10/2=5, and square it, so 25.
3 0
3 years ago
If one inch represents 12 feet, what dimensions would you use to make a scale drawing of a building 75 by 80 feet
viva [34]

Answer:

<u>864000</u>

Step-by-step explanation:

12 feet is one inch so you times the numbers 75x12 and 80x12. 900+960=864000.

3 0
4 years ago
Ray created the list of factors for 48 below.
nasty-shy [4]
The number 7 should be removed from his list to make the list accurate.
3 0
3 years ago
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Find sin(a+B)
diamong [38]

Answer:

Cos A=5/13

we have

Cos² A=1-Sin ²A

25/169=1-Sin²A

sin²A=1-25/169

sin²A=144/169

Sin A=\sqrt{144/169}=12/13

again

Tan B=4/3

P/b=4/3

p=4

b=3

h=\sqrt{3²+4²}=5

Now

Sin B=p/h=4/5

in IV quadrant sin angle is negative so

Sin B=-4/5

CosB=b/h=3/5

Now

<u>S</u><u>i</u><u>n</u><u>(</u><u>A</u><u>+</u><u>B</u><u>)</u><u>:</u><u>s</u><u>i</u><u>n</u><u>A</u><u>c</u><u>o</u><u>s</u><u>B</u><u>+</u><u>C</u><u>o</u><u>s</u><u>A</u><u>s</u><u>i</u><u>n</u><u>B</u>

<u>n</u><u>o</u><u>w</u><u> </u>

<u>substitute</u><u> </u><u>value</u>

<u>Sin(A+B):</u>12/13*3/5+5/13*(-4/5)=36/65-4/13

<u>=</u><u>1</u><u>6</u><u>/</u><u>6</u><u>5</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u>

6 0
3 years ago
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