Suppose x is sold, $280 each , and y is the total financial cost. The first equation in the system is then certainly y = 280x.
The vertex form <span>y-k = a(x-h)^2 where (h,k) is the vertex, and y is the y-intercept.
So, plug the values in.
</span><span>11,000-24,000 = a(0-500)^2
-13,000=250,000a
a=-0.052
y-</span><span>24,000 = -0.052(x-500)^2
y= </span><span>-0.052(x-500)^2 + 24,000
This is the second equation in the system.
The answer is then A, which contain the system </span><span>of equations which can be used to determine must be sold for the company to make a profit.</span>
The solution is shown in the graph attached.
Explanation:
I am goind to teach you how to get that solution.
1) Restricctions: both x and y cannot be negative, i.e.
x ≥ 0 and y ≥ 0⇒ the solution is on the
first quadrant.2) Using the prices of the tickets, $ 8 for adults, and $ 6 for children, the linear equation for the
costs is: cost = 8x + 6y.3) Since the radio station is willing to spend a
maximum of $ 172 you have the final restriction:
⇒ 8x + 6y ≤ 172.4) Then the solutions that meet the three restrictions (x ≥0, y ≥ 0, and 8x + 6y ≤ 172) is found graphically by drawing the line 8 x + 6y = 172
5) To draw the line 8x + 6y = 172, use the axis intercepts:
x = 0 ⇒ y = 172/6 = 86/3 ⇒ point (0, 86/3)
y = 0 ⇒ x = 172/8 = 86/4 ⇒ point (86/4, 0)
6) Once you have the line you
shade the region that is between the line and the two axis. That region contain of the possible solutions.
Answer:
the answer is k=−23/4
Step-by-step explanation:
hoped I helped:)
Four divided by a number n.
I'm sure of it and I hope I helped.