Original Figure:
Length = 15
Width = 5
Height = 10
Volume = Length*Width*Height
Volume = 15*5*10
Volume = 750
New Figure
Length = 3
Width = 1
Height = 2
Each dimension has been divided by 5 (eg: 15/5 = 3)
Volume = Length*Width*Height
Volume = 3*1*2
Volume = 6
The old volume was 750 and it changes to 6
Notice how 750/6 = 125
Which can be rearranged to 750/125 = 6
Answer: if you divide the old volume by 125, then you get the new volume
Note: the new volume is 125 times smaller than the old volume
Put another way, the old volume is 125 times larger compared to the new volume
The fact that 125 = 5^3 is not a coincidence. If you divide each dimension by some number k, then you divide the volume by k^3
5
Is the answer to the craziest answer
Answer:
21.43 miles
Step-by-step explanation:
Let
x ---> the number of miles
y ---> the total cost of rent a car per day
we know that
The linear equation in slope intercept form is equal to
where
m is the slope
b is the y-intercept
we have
<em>sunshine rental company</em>
The slope is equal to
The y-intercept is equal to
substitute
----> equation A
<em> rent me company</em>
The slope is equal to
The y-intercept is equal to
substitute
----> equation B
equate equation A and equation B
solve for x
The number of 11-inch softball is 70 and the number of 12-inch softball is 50.
<u>Step-by-step explanation</u>:
<u>Given that,</u>
- The cost of 11-inch softball = $2.50
- The cost of 12-inch softball = $3.50
<u>Let us assume,</u>
- The number of 11-inch softball be 'x'.
- The number of 12-inch softball be 'y'.
<u>Forming the equation to solve x and y values :</u>
- The total number of softball ordered = 120
- The total cost for 120 softballs = $350
x + y = 120 -------(1)
2.5x + 3.5y = 350 --------(2)
<u>Multiply eq(1) by 2.5 and subtract eq(2) from eq(1)</u>,
2.5x +2.5y = 300
-<u>(2.5x +3.5y = 350)</u>
<u> -1y = -50</u>
Therefore the value of y = 50.
The number of 12-inch softball is 50.
<u>Substitute y=50 in eq(1),</u>
x+50 = 120
x = 120-50
x = 70
The number of 11-inch softball is 70.
Commutative property I hope this helps
