What is the answer when you evaluate n + m -2(m-m) when m = 3 and n = 2?

Solve x to the power of 3 = 8

Nostrana [21]

X^3=8
x^3=2^3
Therefore, x=2

3 0

3 years ago

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The absolute deviation for 3 is

luda_lava [24]

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set.

Find the sum of the data values, and divide the sum by the number of data values.

Find the absolute value of the difference between each data value and the mean: |data value – mean|.

Find the sum of the absolute values of the differences.

Divide the sum of the absolute values of the differences by the number of data values.

3 0

3 years ago

Subtract fractions with different denominators

Tems11 [23]

Answer:

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

Step-by-step explanation:

We know that

A fraction consists of two integers—one on the top, and one on the bottom.
The top one is numerator, the bottom one is denominator, and
These two numbers are separated by a line.

Let us consider two different fractions with different denominators

$\frac{10}{15}$

$\frac{2}{5}$

Lets subtract the two fractions

$\frac{10}{15}-\frac{2}{5}\:\:\:\:$

$\mathrm{Cancel\:}\frac{10}{15}:\quad \frac{2}{3}$

$=\frac{2}{3}-\frac{2}{5}$

$\mathrm{Least\:Common\:Multiplier\:of\:}3,\:5:\quad 15$

$\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}$

$\mathrm{For}\:\frac{2}{3}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:5$

$\frac{2}{3}=\frac{2\cdot \:5}{3\cdot \:5}=\frac{10}{15}$

$\mathrm{For}\:\frac{2}{5}:\:\mathrm{multiply\:the\:denominator\:and\:numerator\:by\:}\:3$

$\frac{2}{5}=\frac{2\cdot \:3}{5\cdot \:3}=\frac{6}{15}$

so

$=\frac{10}{15}-\frac{6}{15}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{10-6}{15}$

$\mathrm{Subtract\:the\:numbers:}\:10-6=4$

$=\frac{4}{15}$

Therefore,

$\frac{10}{15}-\frac{2}{5}=\frac{4}{15}$

5 0

3 years ago

Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorat

mr_godi [17]

Answer:

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

Step-by-step explanation:

We formulate our null and alternative hypotheses as

H0 u≤ 6 ug Ha : u > 6 ug

The significance level ∝ = 0.05

The test statistic used is

t = X` - u / s/ √n

which if H0 is true, has the students' t test with n-1 = 11 degrees of freedom.

The critical region t > t (0.05,11) = 1.796

We compute the t value from the data

Xi Xi²

8.92 79.5664

6.99 48.8601

5.54 30.6916

5.73 32.8329

6.38 40.7044

5.51 30.3601

6.45 41.6025

7.50 56.25

8.48 71.9104

5.56 30.9136

6.90 47.61

6.46 41.7316

80.42 553.0336

Now x` = ∑x/ n = 80.42/12 = 6.70

S²= 1/n-1 ( ∑(xi- x`)²= 1/11 ( 553.034 - (80.42)²/12)

= 1/11 (553.034-538.948) = 1.2805

s= 1.1316

Putting the values in the test statistics

t = X` - u / s/ √n = 6.70- 6 / 1.1316 / √12

= 2.1698

The critical region t > t (0.05,11) = 1.796

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

6 0

3 years ago

Tina practiced piano for 15 hours last month and 45 hours this month. Use multiplication to write a statement comparing the hour

Pani-rosa [81]

Answer: Hours by Tina practiced this month is 3 times the hours she practiced last month such that 15 x 3 =45 hours.

Step-by-step explanation:

Given : Duration of Tina practiced piano last month= 15 hours

Duration of Tina practiced piano this month= 45 hours

We can see 45 is a multiple of 15 such that $45=15\times3$

Therefore, Hours by Tina practiced this month is 3 times the hours she practiced last month such that 15 x 3= 45 hours.

6 0

3 years ago

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