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3 years ago

24x-12x^2=0 What is the result of this(please step by step)

Mathematics

1 answer:

Sav [38]3 years ago

5 0

Okay..
12 x^2 = 24x

12x = 24

x= 2 and x=0

hope it helped

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I am a 2 dimensional shape that had 5 obtuse angles

Montano1993 [528]

Answer:

A pentagon.

Step-by-step explanation:

A pentagon is a 5-sided polygon. Its interior angles each are equivalent to 108°.

108° ≥ 90°, so the angles are obtuse.

Therefore, a 2-D shape with 5 obtuse angles is a <u>pentagon</u>.

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3 years ago

An Individual Retirement Account (IRA) has $17 comma 000in it, and the owner decides not to add any more money to the account

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Step-by-step explanation:

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3 years ago

Which of the following describes the quotient of 4 and -28? A) The quotient is undefined. B) The quotient is an integer. C) The

DanielleElmas [232]

Answer:

-1/7

Step-by-step explanation:

Divide the first expression by the second expression.

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3 years ago

If you are offered one slice from a round pizza (in other words, a sector of a circle) and the slice must have a perimeter of 24

VARVARA [1.3K]

Answer:

A 12 in diameter will reward you with the largest slice of pizza.

Step-by-step explanation:

Let $r$ be the radius and $\theta$ be the angle of a circle.

According with the graph, the area of the sector is given by

$A=\frac{1}{2}r^2\theta$

The arc lenght of a circle with radius $r$ and angle $\theta$ is $r \theta$

The perimeter of the pizza slice is composed of two straight pieces, each of length r inches, and an arc of the circle which you know has length s = rθ inches. Thus the perimeter has length

$2r+r\theta=24 \:in$

We need to express the area as a function of one variable, to do this we use the above equation and we solve for $\theta$

$2r+r\theta=24\\r\theta=24-2r\\\theta=\frac{24-2r}{r}$

Next, we substitute this equation into the area equation

$A=\frac{1}{2}r^2(\frac{24-2r}{r})\\A=\frac{1}{2}r(24-2r)\\A=12r-r^2$

The domain of the area is

$0$

To find the diameter of pizza that will reward you with the largest slice you need to find the derivative of the area and set it equal to zero to find the critical points.

$\frac{d}{dr} A=\frac{d}{dr}(12r-r^2)\\A'(r)=\frac{d}{dr}(12r)-\frac{d}{dr}(r^2)\\A'(r)=12-2r$