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gulaghasi [49]
3 years ago
8

The power in an electrical circuit is given by the equation P= I^2R, where /is

Mathematics
1 answer:
Ganezh [65]3 years ago
7 0

Answer:

P= 12^2 * 100= 14400 W

14400 Watts Its just a calculator work. If you want to use online calculator for clearance please: https://www.rapidtables.com/calc/electric/power-calculator.html

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According to the U.S. Census Bureau, about 63% of Americans are adults (18 and over). Use the U.S. population estimate of 308 mi
Kisachek [45]

Step-by-step explanation:

According to the U.S. Census Bureau, about 63% of Americans are adults (18 and over). Use the U.S. population estimate of 308 million people to calculate the number of American adults in 2010. Round to the nearest hundred thousand adults

4 0
3 years ago
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How many solutions does the equation 6a - 3a - 6 = 2 + 3 have?
Softa [21]

Answer:

One, a=11/3.

Step-by-step explanation:

6a-3a-6=2+3

3a-6=5

3a=5+6

3a=11

a=11/3

5 0
3 years ago
Solve for x<br> -4x &lt; 16<br> ill give brainliest if correct
Firdavs [7]

Answer:

x>-4

Step-by-step explanation:

Hope this helps! Pls give brainliest! Also sub to kgir633 on yt.

4 0
3 years ago
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01. (08.01 LC)
Papessa [141]

Answer:

no solution

Step-by-step explanation:

ya gotta use your eyes and brain huney. it aint that hard. kk? but ill still explain for you.

since x+y=6 and x+y=4. then 4=6. but that is false so no solution.

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6 0
3 years ago
On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
CaHeK987 [17]

Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

  • n=5
  • 2n=10
  • m=4

P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}=0.205

8 0
3 years ago
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