Answer:
155°
Step-by-step explanation:
In Δ ABC, let A = x°
By Angle-sum property,
A + B + C = 180°
But, it is given that C = 130°
So, x + B + 130 = 180
B = 180 - 130 - x
B = 50 - x
Since AD and BD are internal bisectors of A and B,
∠ DAB = x/2 and
∠ DBA =
In Δ ADB, by angle-sum property,
∠ DBA + ∠ DAB +∠ ADB = 180°
+ ∠ ADB = 180°
25 + ∠ ADB = 180°
∠ ADB = 180 - 25 = 155°
Hence, ∠ ADB = 155°
Answer:
Step-by-step explanation:
H
Answer:
α = 27.9794744° ≈ 28.0 m (nearest tenth)
Step-by-step explanation:
Step 1:
Opposite (O) = 42.5 (the side opposite to the reference angle, α)
Adjacent (A) = 80
Hypotenuse (H) = the longest side opposite to the right angle
2. We are given the adjacent (A) and opposite (O) lengths, we would use TOA. Which is:
Tan α = Opp/Adj
Plug in the values
Tan α = 42.5/80
3. Make α stand alone
α = 
4. α = 27.9794744° ≈ 28.0 m (nearest tenth)
If f(x) = 2x + 7 & g(x) = 7 - x
then:
fog = 2(7 - x) + 7
= 14 - 2x + 7
= 21 - 2x
gof = 7 - (2x + 7)
= 7 - 2x - 7
= -2x
gog = 7 - (7 - x)
= 7 - 7 + x
= x