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leonid [27]
3 years ago
14

After spending $3750 for tables and $3650 for chairs a convention center manager finds that the furniture cost 6% more than last

year. Find the amount that he spent last year on tables and chairs.
$6981

$7872

$444

$3883
Mathematics
1 answer:
pshichka [43]3 years ago
7 0

Answer:

$6981

Step-by-step explanation:

Let's find the answer by using the following formula:

(this year cost)=(last year cost)+((last year cost)*(percent increase of cost)) so:

3750+3650=X+0.06X where X=last year cost, then:

7400=1.06X

6981.13=X

In conclusion, last year he spent $6981.

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Solve the inequality y/ -6 is greater than 10
pashok25 [27]
Y<-60 
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3 years ago
BRAINLIEST TO CORRECT HURRY
dlinn [17]

Answer:

-5 5/10, -32/40,5

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2 years ago
Question 6 Multiple Choice Worth 1 points)
OleMash [197]

Answer:

Quantity A because it changes with gravitational pull.

Explanation:

Mass defines the constitutive matter of an object. It is immutable (does not change). Although it could be converted into energy, the matter is constant.

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5 0
2 years ago
Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse
Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

7 0
2 years ago
Please answer this correctly
Evgesh-ka [11]

Answer:

1/9

Step-by-step explanation:

The die has sides 1,2,3,4,5,6

P( less than 5) = 1,2,3,4 / total

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Then rolling again

P(greater than 5) = 6/total = 1/6

P( less than 5,greater than 5) = 2/3* 1/6= 1/9

3 0
3 years ago
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