Given:
Consider the file sizes (in megabytes) for 18 randomly selected files on Gabriel's mp3 player are shown in the below figure.
To find:
The outliers in the distribution.
Solution:
We have, the given data set
2.4, 2.7, 1.6
, 1.3
, 6.2, 1.3, 5.6, 1.1, 2.2, 1.9, 2.1, 4.4, 4.7, 3.0, 1.9, 2.5, 7.5, 5.0
Arrange the data in ascending order.
1.1, 1.3, 1.3, 1.6, 1.9, 1.9, 2.1, 2.2, 2.4, 2.5, 2.7, 3.0, 4.4, 4.7, 5.0, 5.6, 6.2, 7.5,
Divide the data in 4 equal parts.
(1.1, 1.3, 1.3, 1.6), 1.9, (1.9, 2.1, 2.2, 2.4),( 2.5, 2.7, 3.0, 4.4), 4.7, (5.0,5.6, 6.2, 7.5)
It is clear that,





Now,
![Interval=[Q_1-1.5IQR,Q_3+1.5IQR]](https://tex.z-dn.net/?f=Interval%3D%5BQ_1-1.5IQR%2CQ_3%2B1.5IQR%5D)
![Interval=[1.9-1.5(2.8),4.7+1.5(2.8)]](https://tex.z-dn.net/?f=Interval%3D%5B1.9-1.5%282.8%29%2C4.7%2B1.5%282.8%29%5D)
![Interval=[-2.3,8.9]](https://tex.z-dn.net/?f=Interval%3D%5B-2.3%2C8.9%5D)
All the data values lies in the interval [-2.3,8.9]. Therefore, the given data set have no outliers.