Answer:
i'd say it's x=6
Step-by-step explanation:
........
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
In algebraic terms this means x-17>33
Step-by-step explanation:
to solve it x−17>33
1 Add 17 to both sides.
x>33+17
2 Simplify 33+17 to 50
x>50
We will take the common terms in the expressions-
Here in the expression, 3y is a common term.
So,
So, the answer is
42.88. You might want to wait for another answer jyst to be 100% sure:)
