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<h2>
Hello!</h2>
The answer is:
The x-coordinate of the solution to the system of equations is:

<h2>
Why?</h2>
We can solve the problem writing both equations as a system of equations.
So, we are given the equations:

Then, solving by reduction we have:
Multiplying the first equation by 2 in order to reduce the variable "x", we have:


Now, substituting "y" into the first equation, to isolate "x" we have:

Hence we have that the x-coordinate of the solution to the system of equations is

Have a nice day!
Answer: 484
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Work Shown:
First let's compute f(2). We replace every x with 2 and then use PEMDAS to simplify
f(x) = -x^4 + 5x - 4x^2
f(2) = -(2)^4 + 5(2) - 4(2)^2
f(2) = -16 + 5(2) - 4(4)
f(2) = -16 + 10 - 16
f(2) = -6 - 16
f(2) = -22
Then we square this result to find the value of ![[ f(2) ]^2](https://tex.z-dn.net/?f=%5B%20f%282%29%20%5D%5E2)
![f(2) = -22\\\\\left[ f(2) \right]^2 = [ -22 ]^2\\\\\left[ f(2) \right]^2 = 484](https://tex.z-dn.net/?f=f%282%29%20%3D%20-22%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20%5B%20-22%20%5D%5E2%5C%5C%5C%5C%5Cleft%5B%20f%282%29%20%5Cright%5D%5E2%20%3D%20484)
The answer is quadrant 4 or IV
Answer:
we start with -8 divided by 2 because of PEMDAS
we now have -4
then we do 4-4+3=3
Step-by-step explanation: