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Irina18 [472]
3 years ago
13

If AACD ~ AABE, find the value of x.

Mathematics
1 answer:
Anastaziya [24]3 years ago
4 0

9514 1404 393

Answer:

  x = 16

Step-by-step explanation:

Corresponding sides are proportional.

  BE/CD = AE/AD

  20/(3x+8) = (x-1)/(x-1+27)

  20(x+26) = (3x+8)(x -1)

In standard form, this is ...

  3x^2 -15x -528 = 0

  x^2 -5x -176 = 0 . . . . . . divide by 3

  (x -16)(x +11) = 0 . . . . . . . factor

  x = 16

__

This is the positive value that makes the product zero. x=-11 will also make the product 0, but gives negative segment lengths in the geometry. It is an extraneous solution.

You might be interested in
What is -16=p/-3+(-9)
satela [25.4K]

Answer:

192?

Step-by-step explanation:

-16 = p ÷ [-3 + (-9)]

-16 × [-3 + (-9)] = p

-16 × - 12 = p

192 = p

7 0
3 years ago
A rectangular tank that is 2048 ft cubed with a square base and open top is to be constructed of sheet steel of a given thicknes
ira [324]

Answer:

The box should have base 16ft by 16ft and height 8ft Therefore,dimensions are 16 ft by 16 ft by 8 ft

Step-by-step explanation:

We were given the volume of the tank as, 2048 cubic feet.

Form minimum weight, the surface area must be minimum.

Let the height be h and the lengths be x

the volume will be: V=x²h then substitute the value of volume, we have

2048=hx²

hence

h=2048/x²

Since the amount of material used is directly proportional to the surface area, then the material needs to be minimized by minimizing the surface area.

The surface area of the box described is

A=x²+4xh

Then substitute h into the Area equation we have

A= x² + 4x(2048/x²)

A= x² + 8192/x

We want to minimize

A

dA/dx = -8192/x² + 2 x= 0 for max or min

when dA/dx=0

dA/dx= 2x-8192/x²=0

2x=8192/x²

Hence

2x³=8192

x³=4096

x=₃√(4096)

X=16ft

Then h=2048/x²

h=2048/16²

h=8ft

The box should have base 16ft by 16ft and height 8ft

Hence the dimensions are 16 ft by 16 ft by 8 ft

8 0
3 years ago
Help me pleasee<br> Questions r in picture
jok3333 [9.3K]
<h2>Answer:</h2>

\large \bf\implies\frac{12}{61}

<h2>Step-by-step explanation:</h2>

<h2>Given :</h2>

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...

<h2>To Find :</h2>

  • nth term

<h2>Solution :</h2>

We have to add 1 in numerator and -10 in denominator because

\tt \frac{8}{101} , \frac{9}{91} , \frac{10}{81} , \frac{11}{71} ...[Given]

\frac{8  \: + \:  1}{101 \:  - \:  10}  =  \frac{9}{91} \\\\  \frac{9 + 1}{91 - 10}  =  \frac{10}{81}  \\ \\ \frac{10 + 1}{81 - 10}  =  \frac{11}{71}  \\ \\ \frac{11 + 1}{71 - 10}  =  \frac{12}{61} ...

The difference is 1 in numerator so we add 1 and the difference is -10 in denominator so we subtract -10.

4 0
2 years ago
Need help combining like terms
yaroslaw [1]

Answer:

-10x+7.5

Step-by-step explanation:

-2.5(4x-3)

Multiply each term by -2.5

-2.5 * 4x = -10x

-2.5 * 3 = 7.5

-10x + 7.5

7 0
3 years ago
Image on straight line graphs- please help ASAP
MissTica
Plug in (7, 12) for x and y in the equation.

12 = 2(7) + 1
12 = 14 + 1
12 ≠ 15 

Therefore, (7, 12) is not on the straight line equation. 
6 0
3 years ago
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