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3 years ago

If AACD ~ AABE, find the value of x.

Mathematics

1 answer:

Anastaziya [24]3 years ago

4 0

9514 1404 393

Answer:

x = 16

Step-by-step explanation:

Corresponding sides are proportional.

BE/CD = AE/AD

20/(3x+8) = (x-1)/(x-1+27)

20(x+26) = (3x+8)(x -1)

In standard form, this is ...

3x^2 -15x -528 = 0

x^2 -5x -176 = 0 . . . . . . divide by 3

(x -16)(x +11) = 0 . . . . . . . factor

x = 16

This is the positive value that makes the product zero. x=-11 will also make the product 0, but gives negative segment lengths in the geometry. It is an extraneous solution.

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