Answer:
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Explanation:
Following are the program in c#
using System; // namespace
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Tasks
{
class Program
2 // program2
{
static void Main(string[] args) // Main function
{
double num = 958254.73789621; // variables
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Console.Read();
}
}
}
Output:
Format Double : 958254.737
Here we have declared a variable num of type double which store the value num=958254.73789621. To do format with the double number i used a syntax {0:n3}. This syntax {0:n3}is separated with :(colon) here 0 represent the value before the decimal point that is 958254 and n3 represent the value upto 3 decimal points. Hence this statement give the output with three digit after the decimal point .
Answer:
Check the explanation
Explanation:
Here is the program with function definition and two sample calls.
Code:
#include <iostream>
using namespace std;
//checkMe FUNCTION which takes values a, b and c
void checkMe(char &a, int &b, int &c)
{
//if sum of b and c is negative and a is 'n', b and c are set to 0, otherwise a is set to 'p'
if((b+c)<0 && a=='n')
{
b = 0;
c = 0;
}
else
{
a = 'p';
}
}
int main()
{
//first test case when else part is executed
char a = 'n';
int b = 5;
int c = 6;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
//second test case when if part is executed
a = 'n';
b = -4;
c = -5;
checkMe(a, b, c);
cout<<a<<" "<<b<<" "<<c<<endl;
return 0;
}
Kindly check the Output below:
Answer:
B
Explanation:
The point of simulating would be to eliminate the part of having to go through un patential applications and save time.
Answer:
This is a pretty obvious answer.
An unwanted e-mail sent in bulk from people or organizations.
Explanation:
