Answer:
True
Explanation:
This is true because a static class method can be accessed without referring to any objects of the class. When a class member is made static, it's very easy to access the object.
The member becomes static and becomes class level
Answer:
A. Dedicated interconnect
Explanation:
With dedicated interconnect, there is a direct connection between your network and that of Google. It enables you to connect another cloud directly to your Google cloud resources to create hybrid cloud solutions. In other words, Dedicated Interconnect enables hybrid networking. Businesses can now extend their own private cloud into Google's cloud so they can switch control between the two with little latency. This gives them (businesses) control over the amount of data entering into the two clouds.
Answer:
Please check the attachment.
Explanation:
The adjacency matrix is the matrix that has nodes as rows and columns. The nodes if connected is stated as 1 or else 0. And the adjacency list representation is the list with nodes and connected nodes. The nodes that are not connected are not being listed. The diagram and list as well as matrix can be found in the attachment.
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
Answer:
Write a recursive Scheme function power(A, B) that takes two integer parameters, A and B, and returns A raised to the B power. A must be a positive value, but B maybe a negative value.
Explanation:
