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inn [45]
3 years ago
5

ABCd is a parallel. Which statements are true

Mathematics
1 answer:
Leviafan [203]3 years ago
8 0
Confused on the question could I have a picture?
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Someone please help me with this
amid [387]
Simliar-AA is your answer 
7 0
3 years ago
Which is bigger, 7/8" or 9/16"?
Iteru [2.4K]
7/8 and 9/16

7*2/8*2 = 14/16

14/16 and 9/16

Now since we have a common denominator, we can compare the numerators.

14/16 is greater, so 7/8 is greater than 9/16

Answer: 7/8 is bigger
5 0
3 years ago
Read 2 more answers
What is the answer for ( c )
Whitepunk [10]

Answer: 37

Step-by-step explanation:

7 0
2 years ago
A = √7 + √c and b = √63 + √d where c and d are positive integers.
mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

3 0
3 years ago
This is my last question. Please help me!
sesenic [268]

Okay so first you want to simplify the given equation  (7x+3y)(7x-3y)

in order to do this you multiply the first number of the first equation (7x) with the first number of the second equation (7x) this gives you 49x^2

Now you want to multiply the second number of the first equation (3y) by the second number of the second equation (-3y) this gives you -9y^2

Its as easy as pie!

3 0
3 years ago
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