Well, Mathematics can enhance your analytical and problem-solving skills, expands the mind to handle difficult or unfamiliar tasks, and also promotes cautious and careful thinking. Once you know what the words mean you'll be able to write different variable expressions. Like I said it enhances our minds and helps think and solve probelms.
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = ![\frac{85.87}{0.4360}](https://tex.z-dn.net/?f=%5Cfrac%7B85.87%7D%7B0.4360%7D)
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
C) there are no solutions
Step-by-step explanation:
3x-6<3x+13
3x<3x+19
0<19