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Setler79 [48]
3 years ago
9

In a drill, Mark gives Fred a 45 meter head start. After t seconds, Fred is a distance 5t +45 from the starting line andMark is

a distance of 6t from the starting line. How far ahead of Mark is Fred after t seconds?
Mathematics
1 answer:
FromTheMoon [43]3 years ago
7 0

Answer: After t seconds, Fred is far away from Mark by (45-t).

Step-by-step explanation:

Given: Mark gives Fred a 45meter head start.

After t seconds, the distance of  Fred from the starting point = 5t+45

The distance of Mark from the starting point = 6t

Now, Distance between Fred and Mark after t seconds = Location of Fred - Location of Mark

= (5t+45)-6t

= 5t+45-6t

= 45-t

Hence, After t seconds, Fred is far away from Mark by (45-t).

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Answer:

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Step-by-step explanation:

Recall that slope, m, is defined as the ratio rise to run:  rise/run.

Note that if we start at x = -2 (an arbitrary choice), and move 6 units to the right, we end up at x = 4.  This is the 'run.'  Simultaneously, y starts at 1 and decreases to - 6, a change of -7.  

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2 years ago
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torisob [31]

Answer:

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Step-by-step explanation:

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3 years ago
What is the perimeter of a triangle measuring 3 on each side?
ANTONII [103]
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Evgesh-ka [11]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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