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MariettaO [177]
3 years ago
11

Evaluate 2(x + 1) - 3 when x = 6.

Mathematics
1 answer:
alexandr1967 [171]3 years ago
4 0

Evaluate 2(x + 1) - 3 when x = 6.

First, plug in x value.

2(6 + 1) -3   ParenthesisEMDAS

2(7) - 3       PEMultiplyDAS

14 - 3          PEMDASubtract

11 ←

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K to the power of 2-2k-24
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Answer:

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Step-by-step explanation:

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Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9)
IrinaK [193]

Answer:

Equation of the circle   (x-3)²+(y-5)²=(6.4)²

                             x² -6x +9 +y² -10y +25 = 40.96

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given endpoints of diameter P(−2, 1) and Q(8, 9)

Centre of circle = midpoint of diameter

                   Centre = (\frac{-2+8}{2} ,\frac{1+9}{2} )

               Centre (h, k) = (3 , 5)

<u><em>Step(ii):-</em></u>

The distance of two end points

PQ = \sqrt{(x_{2}-x_{1} )^{2} +(y_{2} -y_{1} )^{2}  }

PQ= \sqrt{(8+2 )^{2} +(8 )^{2}  }

PQ = √164 = 12.8

Diameter    d = 2r

                 radius r = d/2

                Radius r = 6.4

<u><em>Final answer:-</em></u>

Equation of the circle  

                    (x-h)²+(y-k)² = r²

                   (x-3)²+(y-5)²=(6.4)²

x² -6x +9 +y² -10y +25 = 40.96

x² -6x  +y² -10y  = 40.96-34

x² -6x  +y² -10y -7= 0

4 0
3 years ago
how do you do this? i don't need it solved i just don't know how to do it. i know the note on the side says how to but i'm still
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Answer:

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Perimeter of triangle K= 19.0 units (3 s.f.)

Step-by-step explanation:

The length of each side of the triangle can be found using the distance formula below:

\boxed{d=  \sqrt{(y1- y2)^{2} + (x1 - x2)^{2}  } }

Please see the attached pictures for full solution.

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257 is the answer to this question
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