Write a system of equations representing the situation to find the price of each large candle, x and each small candle, y.

The ratio of teachers to male students to female students in a school is 3:17:18 if the total number of students in the school i

Artist 52 [7]

Answer: 54

Step-by-step explanation:

First we add 17 plus 18 to dins total number of students I got 35

Then we make ratio

3/35

So we know we have total number of 630 kids then we make a ratio with no teacher so x

X/630

Lin both together then done ☑️

8 0

2 years ago

Which the following is a linear algebraic expression<br><br>pleaseee...help me in math

Serga [27]

Answer:

C 9s-8t

Step-by-step explanation:

A linear expression is an algebraic expression in which each term is either a constant or the product of a constant and (the first power of) a single variable. Linear expression can have one or more variables.

3 0

3 years ago

Find a unit vector in the same direction as the given vector: v = −14.5i + 2.5 j.

Elis [28]

ANSWER

$- \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

EXPLANATION

The given vector is v = −14.5i + 2.5 j.

The magnitude of this vector is

$|v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ {( - 14.5)}^{2} + {2.5}^{2} }$

$v| = \sqrt{ 216.5} = \frac{ \sqrt{866} }{2}$

The unit vector in the direction of this vector is

$= \frac{v}{ |v| }$

$= - \frac{14.5}{ \frac{ \sqrt{866} }{2} } i + \frac{2.5}{ \frac{ \sqrt{866} }{2} } j$

$= - \frac{29}{866} \sqrt{866} i + \frac{5}{866} \sqrt{866} j$

7 0

3 years ago

PLEASE HELP!!

erik [133]

$2.=c.\\\\2\sin4x\cos4x=2\sin(2\cdot4x)=2\sin8x\\\\Used:\\\sin2\alpha=2\sin\alpha\cos\alpha$

$1.=b.\\\\\csc x-\sin x=\dfrac{1}{\sin x}-\dfrac{\sin^2x}{\sin x}=\dfrac{1-\sin^2x}{\sin x}=\dfrac{\cos^2x}{\sin x}\\\\=\dfrac{\cos x\cos x}{\sin x}=\cos x\cdot\dfrac{\cos x}{\sin x}=\cos x\cot x\\\\Used:\\\csc x=\dfrac{1}{\sin x}\\\\\sin^2x+\cos^2x=1\to\cos^2x=1-\sin^2x\\\\\cot x=\dfrac{\cos x}{\sin x}$

$3.=a.\\\\\dfrac{\sin x-1}{\sin x+1}=\dfrac{\sin x-1}{\sin x+1}\cdot\dfrac{\sin x+1}{\sin x+1}=\dfrac{\sin^2x-1^2}{(\sin x+1)^2}=\dfrac{\sin^2x-1}{(\sin x+1)^2}\\\\=\dfrac{-(1-\sin^2x)}{(\sin x+1)^2}=\dfrac{-\cos^2x}{(\sin x+1)^2}\\\\Used:\\(a-b)(a+b)=a^2-b^2\\\\\sin^2x+\cos^2x=1\to \cos^2x=1-\sin^2x$

8 0

3 years ago

Bill is golfing with three friends and can either buy generic golf tees that are packaged by the dozen or the higher quality Aer

natka813 [3]

Answer: at lease 8 packages of Aero flight tees.

Step-by-step explanation:

At least 10 golf tees for each member of his foursome = total of at least 4*10 = 40 tees.

2 packages of the generic golf tees, that are packaged by the dozen = 2*12 = 24 tees.

So, Bill must buy at least 16 Aero tees.

This means he must buy 8 pairs

7 0

3 years ago