Answer: a) $ 32500
b)0.36
Step-by-step explanation:
Given : The amount of insurance (in thousands of dollars) sold in a day by a particular agent is uniformly distributed over the interval [5, 60].
a) The mean value for continuous uniform distribution function with interval [a,b] is given by :-
![\mu=\dfrac{a+b}{2}\\\\=\dfrac{60+5}{2}=32.5](https://tex.z-dn.net/?f=%5Cmu%3D%5Cdfrac%7Ba%2Bb%7D%7B2%7D%5C%5C%5C%5C%3D%5Cdfrac%7B60%2B5%7D%7B2%7D%3D32.5)
Hence, the amount of insurance does the agent sell on an average day = $ 32500.
b) The probability density function = ![\dfrac{1}{60-5}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B60-5%7D)
![=\dfrac{1}{55}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B1%7D%7B55%7D)
Required interval =[40,60]=60-40=20
Now, the probability that the agent sells more than $40,000 of insurance on a particular day :-
![\dfrac{20}{55}=0.36363636\approx0.36](https://tex.z-dn.net/?f=%5Cdfrac%7B20%7D%7B55%7D%3D0.36363636%5Capprox0.36)
Hence, the probability that the agent sells more than $40,000 of insurance on a particular day = 0.36