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Mademuasel [1]
2 years ago
14

Find the prime factorization of 35

Mathematics
2 answers:
zheka24 [161]2 years ago
6 0
The Prime Factors of 35 are 1, 5, 7, 35 and its Factors in Pairs are (1, 35) and (5, 7).
AnnyKZ [126]2 years ago
4 0
<h3>Question:</h3><h3>•Find the prime factorization of 35.</h3>

Answer:

•The Prime Factors of 35 are 1, 5, 7, 35 and its Factors in Pairs are (1, 35) and (5, 7).

<h3>Explanation:</h3>

#Let's Study

#I Hope It's Help

#Keep On Learning

#Carry On Learning

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How do i do this????​
yarga [219]

Blank 1=8

Blank 2=3

Blank 3=11

8 0
3 years ago
Read 2 more answers
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
The data set shows the ages of people riding a bus. What is the mode for this data set? 18 16 11 45 33 11 33 14 18 11
podryga [215]
11 Is the answer I think
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2 years ago
In circle O, tangent MN and secant MPQ are drawn to the circle from exterior point M. If MP = 6 and PQ = 8 then which of the fol
deff fn [24]

Answer:

42

Step-by-step explanation:

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43. Ozzie Foster deposits $2,000 at the end of each year (Ordinary annuity) into an Individ-
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Answer:8349y

Step-by-step explanation:

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