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Mademuasel [1]
2 years ago
14

Find the prime factorization of 35

Mathematics
2 answers:
zheka24 [161]2 years ago
6 0
The Prime Factors of 35 are 1, 5, 7, 35 and its Factors in Pairs are (1, 35) and (5, 7).
AnnyKZ [126]2 years ago
4 0
<h3>Question:</h3><h3>•Find the prime factorization of 35.</h3>

Answer:

•The Prime Factors of 35 are 1, 5, 7, 35 and its Factors in Pairs are (1, 35) and (5, 7).

<h3>Explanation:</h3>

#Let's Study

#I Hope It's Help

#Keep On Learning

#Carry On Learning

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Which statement shows how two polynomials 4x2 and x2 + 3x + 7 demonstrate the closure property when multiplied?
son4ous [18]
By definition we have to:
 A set has under an operation if performance of that operation on set members always produces a member of the same set; in this case we also say that the set is closed under the operation.
 For this case we have the following polynomials:
 4x ^ 2&#10;&#10;x ^ 2 + 3x + 7
 Multiplying we have:
 (4x ^ 2) (x ^ 2 + 3x + 7) = 4x ^ 4 + 12x ^ 3 + 28x ^ 2&#10;
 The product of two polynomials is also a polynomial.
 Answer:
 
d 4x ^ 4 + 12x ^ 3 + 28x ^ 2 is a polynomial
4 0
3 years ago
Green thumb landscaping want to build a $124000.00 greenhouse in 2 years. The company sets up a sinking fund with payments made
DENIUS [597]

Answer:

$<em>150,858.5</em>

Step-by-step explanation:

The formula for calculating compound interest is expressed as;

A = P(1+r/n)^nt

P is the Principal = $124000.00

r is the rate = 12% = 0.12

t is the total time = 2 years

n is the time of compounding = 1/4 = 0.25(quarterly)

Substitute into the formula;

A= 124000(1+0.12/(0.25))^(0.25)(2)

A = 124000(1+0.48)^0.5

A = 124000(1.48)^0.5

A = 124000(1.2166)

A = 150,858.5

<em>The amount after 2 years if compounded quarterly is  150,858.5</em>

8 0
3 years ago
Select all the values that are equivalent to the given expression. Express your answer in scientific notation.
Anna35 [415]

Answer:

the first and last ones

Step-by-step explanation:

5 0
3 years ago
with Judy jogging north and Jackie jogging west (on straight roads). When Jackie is 1 mile farther fro m the intersection than J
miskamm [114]
Let the distance of Judy from intersection is x and distance of Jackie from intersection is y.

We convert the given information to equations, step by step.

Point 1: When Jackie is 1 mile farther from the intersection than Judy.

This means y is 1 mile more than x.

So,

y = 1 + x

Point 2: The distance between them is 2 miles more than Judy’s distance from the intersection. 

Distance between is x+ y.

So, x+y is 2 miles more than y.

x+y = y + 2
⇒
x = 2

From point 1 we have:

y = 1 + x = 1+ 2 = 3

So,

Distance of Judy from intersection is 2 miles and distance of Jackie from intersection is 3 miles.
4 0
3 years ago
The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is ?
Dahasolnce [82]
I Believe The Answer Is 288.
3 0
3 years ago
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