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4 years ago

7

Allison earns a $40,000 base salary plus a commission equal to 15% of your total sales if you are in $70,000 last year what was

her total sales

1 answer:

Anettt [7]4 years ago

5 0

15/100*70000=$10500
$40000+$10500= $50,000

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Round .6283 to the nearest hundredth

Sveta_85 [38]

The answer is-. 63
.0= tenths
.00= hundredths

how to round:
ex. let's say the number is 51 and it says to round to the nearest tens place you look at the new mber before it to round. So you would loom at the 1, keep in mind that any number lower than 5 toy round down. so the answer would be 50. Now consider the number 57 you would round up because 5 or greater you would round up so it would be 60.

6 0

3 years ago

Verify/prove the following trigonometric identity:

myrzilka [38]

Answer:

<em>I </em><em>THINK</em><em> IT</em><em> </em><em>WORKS</em>

<em>TRY</em><em> IT</em><em> </em><em />

7 0

3 years ago

What is the equation of the line with m=2.5 and b=7

mr Goodwill [35]

Y=2.5x+b

Skeleton equation: y=mx+b

4 0

3 years ago

One of the relatively uncommon instances in which researchers know the population standard deviation is in the case of the Intel

Phoenix [80]

Answer:

90% confidence interval for the mean IQ score in this community is [106.58 , 109.42].

Step-by-step explanation:

We are given that in general, the average IQ score in large, diverse populations is 100 and the standard deviation is 15.

Suppose that your sample of 300 members of your community gives you a mean IQ score of 108.

Firstly, the pivotal quantity for 90% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean IQ score = 108

$\sigma$ = population standard deviation = 15

n = sample of members = 300

$\mu$ = population mean IQ score

<em>Here for constructing 90% confidence interval we have used One-sample z test statistics because we know about population standard deviation.</em>

<em />

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.645 < N(0,1) < 1.645) = 0.90 {As the critical value of z at 5% level

of significance are -1.645 & 1.645}

P(-1.645 < $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.645) = 0.90

P( $-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X -\mu}$ < $1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.90

<u>90% confidence interval for</u> $\mu$ = [ $\bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $108-1.645 \times {\frac{15}{\sqrt{300} } }$ , $108+1.645 \times {\frac{15}{\sqrt{300} } }$ ]

= [106.58 , 109.42]

Therefore, we can be 90% confident that the mean IQ score in this community lies between 106.58 and 109.42.

8 0

3 years ago

There are 20 students in a 5th grade class. Four of these students will be selected to be patrols. In how many ways can the four

navik [9.2K]

Answer:

4845 ways

Step-by-step explanation:

We need to form groups of four students among the total of 20 students, and the order of the students inside the group does not matter, so we have a combination problem.

To solve this problem, we just need to find the combination of 20 choose 4:

C(20, 4) = 20! / (16! * 4!) = 20 * 19 * 18 * 17 / (4 * 3 * 2) = 4845

There are 4845 ways of selecting this group of four patrols.

6 0

3 years ago