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3 years ago

1/3 as a number is wat thanks and have a good day aight

Mathematics

1 answer:

podryga [215]3 years ago

5 0

0.33... (it goes on forever)

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Points A, B, C, and D are collinear and

Zanzabum

x=-11

we know that

Points A,B,C,and D are collinear and positioned in that order

AD=AB+BC+CD -----> by addition segment postulate

we have

AB=2x+30

AD=x=32

substitute the given values and solve for x

x+32 = (2x+43)

Group terms that contain the same variable

2x-x=32-43

x=-11

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3 years ago

Find the perimeter of the shape each unit is 1 centimeter

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Answer:

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Step-by-step explanation:

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3 years ago

PLZ HELP ASAP! ILL MARK BRAINLEST!

Sav [38]

Question 1.) Factor completely $12x^{4}+ 6x^{3}+18x^{2}$

Since $6$ divides all the three terms of the equation, so we take $6$ common out from the equation.

i.e., $6(2x^{4}+ 1x^{3}+3x^{2})$

Now, since $x^{2}$ divides all the three terms of the equation, so we take $x^{2}$ common out from the equation.

i.e., $6x^{2}(2x^{2}+ 1x+3)$

Now, this cannot be factored further as $2x^{2}+ 1x+3$ is a quadratic equation and taking out discriminant of it is:

$D = (1)^2 - 4(2)(3)\\ \ \ = 1- 24\\ \ \ = -23$

Since, the discriminant is less than zero. Therefore, the factored form of the given equation : $12x^{4}+ 6x^{3}+18x^{2}$ is : $6x^{2}(2x^{2}+ 1x+3)$

Question 2.) $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$

Since $7$ divides all the three terms of the equation, so we take $7$ common out from the equation.

i.e., $7(x^{3}y+ 2x^{2} y^{3} - x^{2}y^{2})$

Now, since $x^{2}y$ divides all the three terms of the equation, so we take $x^{2}y$ common out from the equation.

i.e., $7x^{2}y(x+ 2y^{2} - y)$

Therefore, the factored form of the given equation : $7x^{3}y+ 14x^{2} y^{3} - 7x^{2}y^{2}$ is : $7x^{2}y(x+ 2y^{2} - y)$

Question 3.) What is the Greatest Common Factor of $x^{6}$ and $x^{3}$ ?

The Greatest Common Factor of two numbers is the biggest number which divides both the given numbers completely.

Now, for the expressions $x^{6}$ and $x^{3}$ :

Since, $x^{3}$ divides both the expressions completely and it is the biggest expression which divides both the expressions.

Therefore, $x^{3}$ is the Greatest Common Factor of $x^{6}$ and $x^{3}$

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3 years ago

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How to solve 1300 ÷ 26 by using multiplication

aleksley [76]

You multiply 26 x 50 that equals 1,300

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3 years ago

ERI has an annual payroll of $3.6 million. The budget allows for $3.86 million. Each entry level employee is paid $45000. How ma

Harrizon [31]

$3,860,000 - $3,600,000= $260,000. $260,000/$45,000= 5.78
5 additional entry level employees

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3 years ago