480=60(v+s)
480=60v+60s
8=v+s
s=8-v...
480=80(v-s) using s from above we get:
480=80(v-(8-v))
6=v-8+v
6=2v-8
2v=14
v=7, and since s=8-v, s=1
So the rate of the team is 7m/s while the rate of the stream is 1m/s
Answer:
w = 1/2
Step-by-step explanation:
One of the ways to solve problems using log is to use these two equations that use the same variables and plug in numbers.
log b (a) = c
b^c = a
By plugging in the numbers we get this:
log 16 (4) = w
16^w = 4
w = 1/2
Answer:
273 = 3 x 7 x 13.
273 is 100010001 in base 2 (binary), 333 in base 9, and 111 in base 16.
The 273rd prime minus the sum of gaps between the first 273 consecutive primes minus 1 equals 273.
273 is the sum of each of two consecutive sums of consecutive numbers: 273 = 36 + 37 + 38 + 39 + 40 + 41 + 42 = 43 + 44 + 45 + 46 + 47 + 48.
False ! ................................................. sorry for all the dots lol
+ 
is your answer.